对包含大括号的大公式进行换行

Question

请帮我将这个等式分成两行。

Q_2(T,V)=V^2\left[1+\left( \frac{3}{2}\right)\left( \frac{2R_1}{3\epsilon}
F\left(\frac{3}{2},\frac{1}{2},\frac{5}{2};\frac{-R_1^2}{\epsilon^2}\right) 
+ \frac{2R_1}{3\epsilon}\frac{\alpha^2 B}{\epsilon^4}
F\left(\frac{3}{10},\frac{1}{2},\frac{3}{10};\frac{-R_1^{10}}{\epsilon^{10}}\right)\right)
\left(\frac{F_0}{R_1T} \right)^3\right]

Answer 1

组内不能有换行符\left ... \right。我建议您首先将所有 替换为\left，\biggl将所有 替换为\right。\biggr然后由您决定align*或multline*环境是否更合适。

\documentclass{article} % or some other suitable document class
\usepackage{amsmath} % for 'align*' and 'multline*' environments
\begin{document}
\noindent
With \verb+align*+:
\begin{align*}
Q_2(T,V)=V^2\biggl[ 1+ \frac{3}{2}\biggl\{ 
& \frac{2R_1}{3\epsilon} 
F\biggl(\frac{3}{2},\frac{1}{2},\frac{5}{2};
  \frac{-R_1^2}{\epsilon^2}\biggr) \\
&+ \frac{2R_1}{3\epsilon}\frac{\alpha^2 B}{\epsilon^4}
F\biggl(\frac{3}{10},\frac{1}{2},\frac{3}{10};
  \frac{-R_1^{10}}{\epsilon^{10}}\biggr)
\biggr\} \biggl(\frac{F_0}{R_1T} \biggr)^{\!\!3}\, \biggr]
\end{align*}


\bigskip\noindent
With \verb+multline*+:
\begin{multline*}
Q_2(T,V)=V^2\biggl[ 1+ \frac{3}{2}\biggl\{ 
 \frac{2R_1}{3\epsilon} 
F\biggl(\frac{3}{2},\frac{1}{2},\frac{5}{2};
  \frac{-R_1^2}{\epsilon^2}\biggr) \\
+ \frac{2R_1}{3\epsilon}\frac{\alpha^2 B}{\epsilon^4}
F\biggl(\frac{3}{10},\frac{1}{2},\frac{3}{10};
  \frac{-R_1^{10}}{\epsilon^{10}}\biggr)
\biggr\} \biggl(\frac{F_0}{R_1T} \biggr)^{\!\!3}\, \biggr]
\end{multline*}
\end{document}

Answer 2

其中一种可能性是使用包multline中定义的数学环境：amsmat

\documentclass{article}
\usepackage{amsmath}

\begin{document}
\begin{multline*}
Q_2(T,V) = V^2g
    \Biggl[1+\left( \frac{3}{2}\right)
    \Biggl(\frac{2R_1}{3\epsilon}F
    \left(\frac{3}{2},\frac{1}{2},\frac{5}{2};\frac{-R_1^2}{\epsilon^2}\right)  \\
    + \frac{2R_1}{3\epsilon}\frac{\alpha^2 B}{\epsilon^4}F
        \left(\frac{3}{10},\frac{1}{2},\frac{3}{10};\frac{-R_1^{10}}{\epsilon^{10}}\right)
    \Biggr)
        \left(\frac{F_0}{R_1T} \right)^3
    \Biggr]
\end{multline*}
\end{document}