我想在文档中打印十六进制转储，其中我为某些特定字节着色。我尝试使用逃出内部然后做文字颜色在我的列表但这会改变文本的格式。字节需要保持对齐。
示例输出：
示例代码：
\lstset{escapeinside={<@}{@>}}
\begin{lstlisting}[language=none, basicstyle=\scriptsize]
01b0 00 00 00 00 00 00 00 00 78 56 34 12 <@\textcolor{blue}{00}@> <@\textcolor{blue}{00}@> 00 01
01c0 <@\textcolor{blue}{01}@> <@\textcolor{blue}{00}@> <@\textcolor{blue}{83}@> <@\textcolor{blue}{fe}@> <@\textcolor{blue}{ff}@> <@\textcolor{blue}{ff}@> 3f 00 00 00 41 29 54 02 00 fe
01d0 ff ff 82 fe ff ff 80 29 54 02 fa e7 1d 00 00 fe
01e0 ff ff 83 fe ff ff 7a 11 72 02 fa e7 1d 00 80 fe
01f0 ff ff 05 fe ff ff 74 f9 8f 02 0c 83 6c 04 <@\textcolor{red}{55}@> <@\textcolor{red}{aa}@>
\end{lstlisting}
有什么方法可以让我保留原来的字体样式吗？清单在逃出内部？
或者，还有更好的方法？
答案1
lstlisting为什么首先需要使用？一个简单的解决方案tabular是：
\documentclass{article}
\usepackage[]{color}
\begin{document}
\begingroup
\ttfamily
\scriptsize
\begin{tabular}{@{}*{17}c@{}}
01b0 & 00 & 00 & 00 & 00 & 00 & 00 & 00 & 00 & 78 & 56 & 34 & 12 & \color{blue}{00} & \color{blue}{00} & 00 & 01 \\
01c0 & \color{blue}{01} & \color{blue}{00} & \color{blue}{83} & \color{blue}{fe} & \color{blue}{ff} & \color{blue}{ff} & 3f & 00 & 00 & 00 & 41 & 29 & 54 & 02 & 00 & fe \\
01d0 & ff & ff & 82 & fe & ff & ff & 80 & 29 & 54 & 02 & fa & e7 & 1d & 00 & 00 & fe \\
01e0 & ff & ff & 83 & fe & ff & ff & 7a & 11 & 72 & 02 & fa & e7 & 1d & 00 & 80 & fe \\
01f0 & ff & ff & 05 & fe & ff & ff & 74 & f9 & 8f & 02 & 0c & 83 & 6c & 04 & \color{red}{55} & \color{red}{aa} \\
\end{tabular}
\endgroup
\end{document}
