将示波器并排放置并垂直居中

Question

我试图将一组节点并排放置（按列对齐）并垂直居中，但失败了。

尽管操作框似乎相对于左侧节点垂直完美居中，但对于右侧节点却并非如此。

我可以每次手动调整移位值，但我正在寻找更好的解决方案。

\begin{figure}[h!]
    \centering
    \begin{tikzpicture}[
        op/.style={shape=rectangle, rounded corners, minimum width=4cm, minimum height=2cm, draw},
        tab/.style={shape=circle, minimum width=1.5cm, draw},
        hyp/.style={shape=circle, double, double distance=2pt, minimum width=1.5cm, draw},
    ]

\begin{scope}[local bounding box=ArgBox]
    \node[tab] (In1) {};
    \node[tab, below=of In1] (InN) {};
    \node at ($(In1)!0.5!(InN)$) {\vdots};
    \node[hyp, below=of InN] (Hyp1) {};
    \node[hyp, below=of Hyp1] (HypN) {};
    \node at ($(Hyp1)!0.5!(HypN)$) {\vdots};
\end{scope}

\begin{scope}[local bounding box=OpBox, shift={($(ArgBox.east)+(5cm,0)$)}]
    \node[op] (Op) {Operation};
\end{scope}

\begin{scope}[local bounding box=OutBox, shift={($(OpBox.east)+(5cm,0)$)}]
    \node[tab] (Out1) {};
    \node[tab, below=of Out1] (Out2) {};
    \node[tab, below=of Out2] (OutN) {};
    \node at ($(Out2)!0.5!(OutN)$) {\vdots};
\end{scope}

\draw[->] (In1) -- node [above, sloped] {arg \#1} (Op);
\draw[->] (InN) -- node [above, sloped] {arg \#N} (Op);
\draw[->] (Op) -- node [above, sloped] {out \#1} (Out1);
\draw[->] (Op) -- node [above, sloped] {out \#2} (Out2);
\draw[->] (Op) -- node [above, sloped] {out \#N} (OutN);
\draw[->] (Hyp1) -- node [above, sloped] {hyp \#1} (Op);
\draw[->] (HypN) -- node [above, sloped] {hyp \#N} (Op);
\end{tikzpicture}
    \caption{Caption}
    \label{fig:my_label}
\end{figure}

谢谢！

编辑：我想要的是，无论左节点、操作框和右节点有多少个，它们始终位于中心。

Answer 1

像这样：

使用arrows.meta、calc、chains和图像代码可以写成positioning：quotes

\documentclass[border=2mm,tikz]{standalone}
\usetikzlibrary{arrows.meta,
                calc, chains,
                positioning,
                quotes}
\usepackage{bm}
                
\begin{document}
\begin{tikzpicture}[
node distance = 7mm and 22mm, 
  start chain = going below,
    op/.style = {shape=rectangle, rounded corners, minimum size=12mm, draw},
    vd/.style = {midway, text depth=0.25ex, text height=2.5ex,
                 inner ysep=0pt, node contents={$\bm{\vdots}$}},
   tab/.style = {shape=circle, minimum width=9mm, draw},
   hyp/.style = {tab, double},
       every edge/.style = {draw, -Straight Barb, shorten >=1pt, shorten <=1pt},
every edge quotes/.style = {auto, font=\footnotesize, sloped}
                    ]
% left in nodes
    \begin{scope}[nodes={on chain}]
\node[tab] (In1) {};
\node[tab] (InN) {};
\node[hyp] (Hyp1) {};
\node[hyp] (HypN) {};
    \end{scope}
\path   (In1) -- (InN)  node[vd] 
       (Hyp1) -- (HypN) node[vd]; 
% operation
\node[op, right=of $(In1)!0.5!(HypN)$] (Op) {Operation};
% right out nodes
    \begin{scope}[nodes={on chain}]
\node[tab, above right=of Op] (Out1) {};
\node[tab] (Out2) {};
\node[tab] (OutN) {};
\end{scope}
\path   (Out2) -- (OutN) node[vd];
% arrows
\draw   (In1) edge ["arg \#1"]  (Op)
        (InN) edge ["arg \#N"]  (Op)
        (Op)  edge ["out \#1"]  (Out1)
        (Op)  edge ["out \#2"]  (Out2)
        (Op)  edge ["out \#N"]  (OutN)
        (Hyp1) edge ["hyp \#1"] (Op)
        (HypN) edge ["hyp \#N"] (Op);
\end{tikzpicture}
\end{document}

附录： 更通用的“半自动”解决方案:)。它需要：

• 节点垂直距离必须与tab 节点直径相等（命令\vnd）
• 对于水平距离必须定义为水平长度作为命令´（\hnd
• 定义输出节点数 ( \NUM)
• 到链的右输出节点应该插入\NUM节点
• 用于计算右链中第一个节点的位置的宏被定义\K。通过它，这个位置被计算为above right=\K*\vnd and \hnd of Op.east
• 右链为垂直链，其计算量为(<tab minimum size>-<(inserted square minimum size)/2>

7 个输出节点的 MWE：

\documentclass[border=2mm,tikz]{standalone}
\usetikzlibrary{arrows.meta,
                calc, chains,
                positioning,
                quotes}
\usepackage{bm}

\begin{document}
\begin{tikzpicture}[
node distance = \vnd and \hnd,
  start chain = going below,
    op/.style = {shape=rectangle, rounded corners, 
                 minimum size=12mm, 
                 draw},
    vd/.style = {midway, text depth=0.25*\vnd, text height=0.75*\vnd,
                 inner ysep=0pt, node contents={$\bm{\vdots}$}},
   tab/.style = {shape=circle, 
                 minimum size=\vnd, inner sep=0pt, outer sep=0pt, draw},
   hyp/.style = {tab, double},
       every edge/.style = {draw, -Straight Barb, shorten >=1pt, shorten <=1pt},
every edge quotes/.style = {auto, font=\footnotesize, inner sep=2pt, sloped}
                    ]
\def\vnd{ 6 mm} % minimum size is 6mm
\def\hnd{21 mm}
\def\NUM{7}     % number of output nodes
\pgfmathsetmacro{\K}{0.5*int(2*\NUM+1)-2} 

% left input nodes
    \begin{scope}[nodes={on chain}]
\node[tab] (In1) {};
\node[tab] (InN) {};
\node[hyp] (Hyp1) {};
\node[hyp] (HypN) {};
    \end{scope}
\path   (In1) -- (InN)  node[vd]
       (Hyp1) -- (HypN) node[vd];
% operation
\node[op, right=of $(In1.east)!0.5!(HypN.east)$] (Op) {Operation};
% right output nodes, 
    \begin{scope}[nodes={yshift=0.29289 mm, on chain}]
\node[tab, above right=\K*\vnd and \hnd of Op.east] (Out1) {};
\node[tab] (Out2) {};
\node[tab] (OutN) {};
\node[hyp] (Hyp1) {};
\node[hyp]  (Hyp2) {};
\node[tab]  (OutM) {};
\node[hyp]  (Hyp4) {};
    \end{scope}
\path (Out2) -- (OutN)  node[vd];
% arrows
\draw   (In1) edge ["arg \#1"]  (Op)
        (InN) edge ["arg \#N"]  (Op)
       (HypN) edge ["hyp \#N"]  (Op)
        (Op)  edge ["out \#1"]  (Out1)
        (Op)  edge ["out \#2"]  (Out2)
        (Op)  edge ["out \#N"]  (OutN)
        (Op)  edge ["hyp \#1"]   (Hyp1)
        (Op) edge ["hyp \#1"]   (Hyp4)
        ;
 \end{tikzpicture}
\end{document}

\NUM=3 的结果与第一个答案相同，\num=4 的结果为

对于 \NUM=7 则为