TikZ 绘制三角剖分

Question

有人可以帮忙在 TIKZ 上重现这个问题吗？

Answer 1

具有两个 foreach 循环的解决方案

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{calc}

\begin{document}
\begin{tikzpicture}

\foreach \aa in {0,1,2,...,5}{
    \draw (0,0)coordinate(O) -- ({\aa*360/5}:2)coordinate(P\aa);
}

\draw 
(P0) 
\foreach \aa in  {1,2,...,5}{--
(P\aa)
}
-- cycle;
\draw[fill] (O) circle (1mm);
\end{tikzpicture}

\end{document}

Answer 2

您可以使用名为的工具自行创建快速解决方案数学。

\documentclass[12pt]{article}
\usepackage{amsmath}
\usepackage{tikz}
\begin{document}
\tikzset{every picture/.style={line width=0.75pt}}
\begin{tikzpicture}[x=0.75pt,y=0.75pt,yscale=-1,xscale=1]
\draw   (259.15,107.06) -- (342.34,167.5) -- (310.57,265.29) -- (207.74,265.29) -- (175.97,167.5) -- cycle ;
%Straight Lines [id:da5500931558328854] 
\draw    (259.15,107.06) -- (259.15,194.53) ;
%Straight Lines [id:da9807314972174233] 
\draw    (175.97,167.5) -- (259.15,194.53) ;
%Straight Lines [id:da4619344120764781] 
\draw    (342.34,167.5) -- (259.15,194.53) ;
%Straight Lines [id:da9720784168022731] 
\draw    (259.15,194.53) -- (207.74,265.29) ;
%Straight Lines [id:da3200168995877415] 
\draw    (259.15,194.53) -- (310.57,265.29) ;
%Shape: Circle [id:dp3653706700614776] 
\draw  [fill={rgb, 255:red, 0; green, 0; blue, 0 }  ,fill opacity=1 ] (254.65,194.53) .. controls (254.65,192.04) and (256.67,190.03) .. (259.15,190.03) .. controls (261.64,190.03) and (263.65,192.04) .. (263.65,194.53) .. controls (263.65,197.02) and (261.64,199.03) .. (259.15,199.03) .. controls (256.67,199.03) and (254.65,197.02) .. (254.65,194.53) -- cycle ;
\draw (268,190.4) node [anchor=north west][inner sep=0.75pt]    {\large $A_{i}$};
\end{tikzpicture}
\end{document}

Answer 3

如果绘制的形状是正五边形，那么我将利用 TikZ 库regular polygon（参见 TikZ 和 PGF 手册，第 792 页，版本 3.1.7a）：

\documentclass[tikz, margin=3.14159]{standalone}
\usetikzlibrary{shapes.geometric}

\begin{document}
    \begin{tikzpicture}
\node (s)   [regular polygon, regular polygon sides=5, draw,
             minimum size=33mm] {$\bullet$};
\foreach \i in {1,2,...,5}
    \draw (0,0) -- (s.corner \i);
    \end{tikzpicture}
\end{document}