\input luaotfload.sty
\font\bsk=[BaskervilleMTPro-Regular]:script=latn;
\bsk
If the dimension $M$ were less than the number $N$ of data sites, then the columns of $A$ couldn’t span the whole of~$R^N$, so there would be some sets of data values~$F$ for which there is no interpolant in the space of functions~$S$; if instead~$M$ were greater than~$N$, \dots
\bye
我正在纯 luatex 中加载系统上安装的 otf 字体。当我使用script=latn具有启用连字效果的功能时，出现了一个奇怪的问题：如果我删除~之前的字符$R^N$，并代之以空格，则“of”和“R^N”之间的打印空格会略微增加。这是怎么回事？
（带追踪）
\input luaotfload.sty
\font\bsk=[BaskervilleMTPro-Regular]:script=latn;
\bsk
\tracingonline1
\tracingoutput1
\showboxdepth\maxdimen
\showboxbreadth\maxdimen
If the dimension $M$ were less than the number $N$ of data sites, then
the columns of $A$ couldn’t span the whole of~$R^N$, so there would be
some sets of data values~$F$ for which there is no interpolant in the
space of functions~$S$; if instead~$M$ were greater than~$N$, \dots
If the dimension $M$ were less than the number $N$ of data sites, then
the columns of $A$ couldn’t span the whole of $R^N$, so there would be
some sets of data values~$F$ for which there is no interpolant in the
space of functions~$S$; if instead~$M$ were greater than~$N$, \dots
\bye
这是日志文件
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...\hbox(1.05554+0.0)x11.66661, direction TLT
....\teni :
....\glue(\thinmuskip) 1.66663
....\teni :
....\glue(\thinmuskip) 1.66663
....\teni :
...\glue 1.66663
...\mathoff
...\penalty 10000
...\glue(\parfillskip) 0.0 plus 1.0fil
...\glue(\rightskip) 0.0
..\glue 0.0 plus 1.0fill
.\glue(\baselineskip) 17.55556
.\hbox(6.44444+0.0)x469.75499, glue set 232.37749fil, direction TLT
..\glue 0.0 plus 1.0fil minus 1.0fil
..\tenrm 1
..\glue 0.0 plus 1.0fil minus 1.0fil
{/usr/local/texlive/2020/texmf-var/fonts/map/pdftex/updmap/pdftex.map})</home/ma
tteo/texmf/fonts/opentype/monotype/BaskervilleMTPro/BaskervilleMTPro-Regular.otf
></usr/local/texlive/2020/texmf-dist/fonts/type1/public/amsfonts/cm/cmmi10.pfb><
/usr/local/texlive/2020/texmf-dist/fonts/type1/public/amsfonts/cm/cmmi7.pfb></us
r/local/texlive/2020/texmf-dist/fonts/type1/public/amsfonts/cm/cmr10.pfb>
Output written on test.pdf (1 page, 28680 bytes).
PDF statistics: 27 PDF objects out of 1000 (max. 8388607)
17 compressed objects within 1 object stream
0 named destinations out of 1000 (max. 131072)
1 words of extra memory for PDF output out of 10000 (max. 100000000)
根据 Marcel Krüger 的建议，问题可能出在 f 和空格之间插入的字距调整，而 则已禁用该调整\penalty10000。~以下是有关此字体中字符“f”的字距调整的信息。
答案1
Marcel 可能会在 luaotfload 中修复这个问题，但解决方法可能是......
我找不到具有空格的字距的字体，因此我复制了 TeX Gyre Termes，并使用 fontforge 为 f-space 添加了一对（过大的）值 1000，因此效果很明显。
令人惊讶的是，如果你直接看空格，\lastskip你会看到一个正常的单词空格，但是此代码提取了前一个字符并制作了一个框来提取修改后的粘合节点并在添加了 nobreak 惩罚后添加。
\input luaotfload.sty
\font\bsk=[./texgyretermes-regular-fspace.otf]:script=latn;
\bsk
\tracingonline1
\tracingoutput1
\showboxdepth\maxdimen
\showboxbreadth\maxdimen
If the dimension $M$ were less than the number $N$ of data sites, then
the columns of $A$ couldn’t span the whole of~$R^N$, so there would be
some sets of data values~$F$ for which there is no interpolant in the
space of functions~$S$; if instead~$M$ were greater than~$N$, \dots
\protected\def~{\directlua{
local n=tex.nest[tex.nest.ptr].tail
if (n.id==29) % glyph
then
tex.sprint('\detokenize{\\setbox0\\hbox{\\char' .. n.char .. '\\spacefactor=1000{} }\\setbox0\\hbox{\\unhbox0 \\global\\skip1\\lastskip}\\nobreak\\hskip\\skip1\\relax}')
else
tex.sprint('\detokenize{\\leavevmode\\nobreak\\ }')
end
}}
If the dimension $M$ were less than the number $N$ of data sites, then
the columns of $A$ couldn’t span the whole of~$R^N$, so there would be
some sets of data values~$F$ for which there is no interpolant in the
space of functions~$S$; if instead~$M$ were greater than~$N$, \dots
If the dimension $M$ were less than the number $N$ of data sites, then
the columns of $A$ couldn’t span the whole of $R^N$, so there would be
some sets of data values~$F$ for which there is no interpolant in the
space of functions~$S$; if instead~$M$ were greater than~$N$, \dots
\bye