IEEE 论文格式的表格

Question

我正在尝试使用下面的包来创建下面的表格，但是它的格式不是很好组织，特别是数字，因为它们需要位于中心和标签中。有人可以帮忙使表格更具可调性并且看起来更专业吗？

\documentclass[conference]{IEEEtran}
\IEEEoverridecommandlockouts

\usepackage{booktabs,tabulary,lipsum}
\usepackage{dcolumn,tipa}
\newcolumntype{d}{D{.}{.}{6.5}}
\usepackage{siunitx}
\usepackage[usestackEOL]{stackengine}
\usepackage{multirow}


\begin{document}

\begin{table*}[ht]
\caption{Table ex.}
\label{tab1}
\centering
\renewcommand\footnoterule{\kern -1ex}
\renewcommand{\arraystretch}{1.3}
\begin{tabular*}{\linewidth}{l*{9}{d}}
\toprule \multirow{3}{*}{Subjects}   & 

\multicolumn{4}{c}{Numbers} & 
\multicolumn{4}{c}{Numbers}\\
\cmidrule(r){2-5}\cmidrule(l){6-9}  &
\multicolumn{1}{c}{XYZ} & 
\multicolumn{1}{c}\addstackgap{\stackanchor{XYZ}{(Numbers)}} & 
\multicolumn{1}{c}{Numbers Tree} & 
\multicolumn{1}{c}{Numbers Tree} & 
\multicolumn{1}{c}{XYZ} & 
\multicolumn{1}{c}\addstackgap{\stackanchor{XYZ}{(Numbers)}} & 
\multicolumn{1}{c}{Numbers Tree} & 
\multicolumn{1}{c}{Numbers Tree} \\\midrule 
 
X1 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\

X2 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 

X3 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 

X4 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 

X5 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\\bottomrule
\end{tabular*}

\end{table*}

\end{document}

结果是这样的：

Answer 1

您应该使用S的列siunitx。

 \documentclass[conference]{IEEEtran}
 \IEEEoverridecommandlockouts

 \usepackage{booktabs,tabulary,lipsum}
 \usepackage{dcolumn,tipa}
 \newcolumntype{d}{D{.}{.}{6.5}}
 \usepackage{siunitx}
 \usepackage[usestackEOL]{stackengine}
 \usepackage{multirow}


 \begin{document}

 \begin{table*}[ht]
 \sisetup{
 table-number-alignment = center,
 table-figures-integer = 1,
 table-figures-decimal = 4
 }
 \caption{Table ex.}
 \label{tab1}
 \centering
 \renewcommand\footnoterule{\kern -1ex}
 \renewcommand{\arraystretch}{1.3}
 \begin{tabular}{l*{8}{S}}
 \toprule \multirow{3}{*}{Subjects}   & 
 \multicolumn{4}{c}{Numbers} & 
 \multicolumn{4}{c}{Numbers}\\
 \cmidrule(r){2-5}\cmidrule(l){6-9}  &
 \multicolumn{1}{c}{XYZ} & 
 \multicolumn{1}{c}\addstackgap{\stackanchor{XYZ}{(Numbers)}} & 
 \multicolumn{1}{c}{Numbers Tree} & 
 \multicolumn{1}{c}{Numbers Tree} & 
 \multicolumn{1}{c}{XYZ} & 
 \multicolumn{1}{c}\addstackgap{\stackanchor{XYZ}{(Numbers)}} & 
 \multicolumn{1}{c}{Numbers Tree} & 
 \multicolumn{1}{c}{Numbers Tree} \\\midrule 
 X1 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\
 X2 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 
 X3 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 
 X4 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 
 X5 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\\bottomrule
 \end{tabular}

 \end{table*}

 \end{document}

Answer 2

您的表格的主要问题是选择 来6.5格式化 8 个数字列，但这种选择并不恰当；它应该1.4贯穿始终。第二个问题是您使用了tabular*环境，但 LaTeX 没有机会实现所需的整体宽度（此处：\linewidth）。最后，只有 8 个（而不是 9 个）类型的列d。

\documentclass[conference]{IEEEtran}
\IEEEoverridecommandlockouts

\usepackage{booktabs}
\usepackage{dcolumn,tipa}
\newcolumntype{d}[1]{D{.}{.}{#1}} % let the 'd' column type take an argument
%\usepackage{siunitx}             % not needed for this example
\usepackage[usestackEOL]{stackengine}
\usepackage{multirow}
\newcommand\mcc[1]{\multicolumn{1}{c}{#1}} % handy shortcut macro

\begin{document}

\begin{table*}[ht]
\caption{Table example}
\label{tab1}
%%\centering % redundant
%%\renewcommand\footnoterule{\kern -1ex} % What is this instruction doing here??
\renewcommand{\arraystretch}{1.3}
\setlength\tabcolsep{0pt} % make LaTeX figure out the intercolumn separation
\begin{tabular*}{\linewidth}{@{\extracolsep{\fill}} l *{8}{d{1.4}} } % '1.4', not '6.5'
\toprule 
\multirow{3}{*}{Subjects} & \multicolumn{4}{c}{Numbers} & \multicolumn{4}{c}{Numbers}\\
\cmidrule{2-5} \cmidrule{6-9} &
\mcc{XYZ} & \mcc{\addstackgap{\stackanchor{XYZ}{(Numbers)}}} & 
\mcc{Numbers Tree} & \mcc{Numbers Tree} & 
\mcc{XYZ} & \mcc{\addstackgap{\stackanchor{XYZ}{(Numbers)}}} & 
\mcc{Numbers Tree} & \mcc{Numbers Tree} \\
\midrule 
X1 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 
X2 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 
X3 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 
X4 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\ 
X5 & 0.5000 & 0.4888 & 0.0112 & 0.0001 & 0.8500 & 0.3540 & 0.2332 & 0.2367 \\
\bottomrule
\end{tabular*}
\end{table*}
\end{document}