我需要在 Latex Beamer 的一个框架上有两列。
我希望两个 tikzpictures 具有完全相同的大小（节点大小应相等）并且所有文本位于相同的高度，例如 H 的定义应与 G 位于同一行，F' 的定义应与 F 位于同一行。
我怎么也想不通。
任何帮助都值得感激！
平均能量损失
\documentclass{beamer}
\usepackage{graphicx}
\usepackage{adjustbox}
\usepackage{tikz}
\begin{document}
\begin{frame}
\frametitle{Satz 6}
\begin{columns}
\begin{column}{0.5\textwidth}
\centering
\begin{adjustbox}{max totalsize={\textwidth}{\textheight},center}
\begin{tikzpicture}[
state/.style={circle, draw, minimum size=2.5em}]
\node[state] (n6) at (1,10) {6};
\node[state] (n4) at (4,8) {4};
\node[state] (n5) at (8,9) {5};
\node[state] (n3) at (5,5) {3};
%\node[state] (n7) at (2,5) {7};
%\node[state] (n8) at (-2,4) {8};
%\node[state] (n9) at (0,1) {9};
%\node[state] (n10) at (1.5,3) {10};
% labels
%\node[scale=1.5] at (-2,10) {$G = H + T$};
%\node[scale=1] at (-0.5,5.5) {$H = (V_H, E_H)$};
\node[scale=2] at (5,12) {$H = (V', E')$};
\node[scale=2] at (5,3) {$F' = \{4\}$};
%\foreach \from/\to [count=\xi] in {n6/n4,n4/n5,n5/n1,n1/n2,n2/n5,n2/n3,n3/n4, n5/n3}
%\draw (\from) -- (\to) node [midway, label=\xi] {};
\draw (n4) -- (n5) node [midway] {};
\draw (n4) -- (n6) node [midway] {};
\draw (n3) -- (n4) node [midway] {};
\draw (n3) -- (n5) node [midway] {};
\end{tikzpicture}
\end{adjustbox}
\end{column}
\begin{column}{0.5\textwidth}
\centering
\begin{adjustbox}{max totalsize={\textwidth}{\textheight},center}
\begin{tikzpicture}[
state/.style={circle, draw, minimum size=2.5em}]
\node[state] (n6) at (1,10) {6};
\node[state] (n4) at (4,8) {4};
\node[state] (n5) at (8,9) {5};
\node[state] (n1) at (11,8) {1};
\node[state] (n2) at (9,6) {2};
\node[state] (n3) at (5,5) {3};
%\node[state] (n7) at (2,5) {7};
%\node[state] (n8) at (-2,4) {8};
%\node[state] (n9) at (0,1) {9};
%\node[state] (n10) at (1.5,3) {10};
% labels
%\node[scale=1.5] at (-2,10) {$G = H + T$};
%\node[scale=1] at (-0.5,5.5) {$H = (V_H, E_H)$};
\node[scale=2] at (5,12) {$G = (V, E)$};
\node[scale=2] at (5,2) {$F = \{2\}$};
\node[scale=2] at (5,1) {$F' \cup F = \{2,4\}$};
%\foreach \from/\to [count=\xi] in {n6/n4,n4/n5,n5/n1,n1/n2,n2/n5,n2/n3,n3/n4, n5/n3}
%\draw (\from) -- (\to) node [midway, label=\xi] {};
\draw (n1) -- (n2) node [midway] {};
\draw (n1) -- (n5) node [midway] {};
\draw (n2) -- (n5) node [midway] {};
\draw (n2) -- (n3) node [midway] {};
\draw (n4) -- (n5) node [midway] {};
\draw (n4) -- (n6) node [midway] {};
\draw (n3) -- (n4) node [midway] {};
\draw (n3) -- (n5) node [midway] {};
\end{tikzpicture}
\end{adjustbox}
\end{column}
\end{columns}
\end{frame}
\end{document}
答案1
\documentclass{beamer}
\usepackage{graphicx}
\usepackage{tikz}
\begin{document}
\begin{frame}
\frametitle{Satz 6}
\begin{columns}
\begin{column}[t]{0.4\textwidth}
\centering
\begin{tikzpicture}[scale=0.5,baseline=(current bounding box.north),
state/.style={circle, draw, minimum size=2em}]
\node[state] (n6) at (1,10) {6};
\node[state] (n4) at (4,8) {4};
\node[state] (n5) at (8,9) {5};
\node[state] (n3) at (5,5) {3};
\node at (5,12) {$H = (V', E')$};
\node at (5,3) {$F' = \{4\}$};
\draw (n4) -- (n5) node [midway] {};
\draw (n4) -- (n6) node [midway] {};
\draw (n3) -- (n4) node [midway] {};
\draw (n3) -- (n5) node [midway] {};
\end{tikzpicture}
\end{column}
\begin{column}[t]{0.6\textwidth}
\centering
\begin{tikzpicture}[scale=0.5,baseline=(current bounding box.north),
state/.style={circle, draw, minimum size=2em}]
\node[state] (n6) at (1,10) {6};
\node[state] (n4) at (4,8) {4};
\node[state] (n5) at (8,9) {5};
\node[state] (n1) at (11,8) {1};
\node[state] (n2) at (9,6) {2};
\node[state] (n3) at (5,5) {3};
\node at (5,12) {$G = (V, E)$};
\node at (5,3) {$F = \{2\}$};
\node at (5,2) {$F' \cup F = \{2,4\}$};
\draw (n1) -- (n2) node [midway] {};
\draw (n1) -- (n5) node [midway] {};
\draw (n2) -- (n5) node [midway] {};
\draw (n2) -- (n3) node [midway] {};
\draw (n4) -- (n5) node [midway] {};
\draw (n4) -- (n6) node [midway] {};
\draw (n3) -- (n4) node [midway] {};
\draw (n3) -- (n5) node [midway] {};
\end{tikzpicture}
\end{column}
\end{columns}
\end{frame}
\end{document}