使用 tikz、arc 创建分割椭圆

Question

我正在尝试使用 tikz 和 arc 命令创建一个椭圆（分割）。

半长轴 a = 5 半短轴 b = 3

各点的坐标：O(0,0); A(4.797,0.846); B(0.526,2.983); C(-0.526,2.983); D(-4.797,0.846); E(-4.797,0.846); F(-0.526,-2.983); G(0.526,-2.983); H(4.797,-0.846);

OA 与 x 轴形成的角为 10 度 OB 与 x 轴形成的角为 80 度 OC 与 x 轴形成的角为 100 度 OD 与 x 轴形成的角为 170 度 OE 与 x 轴形成的角为 190 度 OF 与 x 轴形成的角为 260 度 OG 与 x 轴形成的角为 280 度 OH 与 x 轴形成的角为 350 度

我使用了以下内容，结果也附在附件中。

\begin{tikzpicture}
\draw (4.797,0.846) arc(10:80:5cm 和 3 cm); \draw (-0.526,2.983) arc(100:170:5cm 和 3 cm); \end{tikzpicture}

请提出修正建议以创建正确的分割椭圆。

Answer 1

我建议您只用以下方法镜像一个椭圆scope：对于变粗的线条，我使用了\edge。

\documentclass[border=3.41mm]{standalone}
\usepackage{tikz}
\begin{document}
    

\begin{tikzpicture}
    
    %axis
    \draw (0,-8) -- (0,8);
    \draw[] (-8,0)-- +(15,0) edge[thick] (8,0);
    
    % original ellipse
    \draw[thick] (4.797,0.846) arc(10:80:5cm and 3 cm);
    \node[xshift=5pt,yshift=-10](a) at (4.79,0.85) {A};
    \node[yshift=5pt,xshift=-10pt](b) at (0.75,3.28) {B};

    \draw[] (0,0)-- +(4.79,0.85) edge[thick] (8,1.45); % A line
    \draw[] (0,0)-- +(0.75,3.28) edge[thick] (1,4.5); % B line
    \draw[<->,>=stealth] (8,0) arc(0:28:2cm and 3 cm) node[midway,xshift=10pt]{10°};
    \draw[<->,>=stealth] (7,0) arc(0:80:7.25cm and 4.5 cm) node[midway,yshift=10pt]{80°};

    % mirror ellipse
    \begin{scope}[yscale=1,xscale=-1]
        \draw[thick] (4.797,0.846) arc(10:80:5cm and 3 cm);
        \node[xshift=-5pt](a) at (4.79,0.85) {D};
        \node[yshift=5pt](b) at (0.75,3.28) {C};
        \draw[] (4.79,0.85) -- (0,0);
        \draw[] (0.75,3.28) -- (0,0);
    \end{scope}

    % mirror ellipse
    \begin{scope}[yscale=-1,xscale=-1]
        \draw[thick] (4.797,0.846) arc(10:80:5cm and 3 cm);
        \node[xshift=-5pt](a) at (4.79,0.85) {E};
        \node[yshift=-5pt](b) at (0.75,3.28) {F};
        \draw[] (4.79,0.85) -- (0,0);
        \draw[] (0.75,3.28) -- (0,0);
    \end{scope}

    % mirror ellipse
    \begin{scope}[yscale=-1,xscale=1]
        \draw[thick] (4.797,0.846) arc(10:80:5cm and 3 cm);
        \node[xshift=5pt](a) at (4.79,0.85) {G};
        \node[yshift=-5pt](b) at (0.75,3.28) {H};
        \draw[] (4.79,0.85) -- (0,0);
        \draw[] (0.75,3.28) -- (0,0);
    \end{scope}

    \node[xshift=7pt,yshift=-7pt](o) at (0,0) {O};
    
\end{tikzpicture}

\end{document}

Answer 2

以下代码生成了所需的图像。谢谢大家。我现在更能理解范围和比例命令了。

% original ellipse
\draw[line width=1.5pt] (10:5 and 3) arc(10:80:5cm and 3 cm);

% mirror ellipse
\begin{scope}[yscale=1,xscale=-1]
    \draw[line width=1.5pt] (10:5 and 3) arc(10:80:5cm and 3 cm);
\end{scope}

% mirror ellipse
\begin{scope}[yscale=-1,xscale=-1]
    \draw[line width=1.5pt] (10:5 and 3) arc(10:80:5cm and 3 cm);
\end{scope}

% mirror ellipse
\begin{scope}[yscale=-1,xscale=1]
    \draw[line width=1.5pt] (10:5 and 3) arc(10:80:5cm and 3 cm);
\end{scope}