![tikzpicture、费曼、方程](https://linux22.com/image/435255/tikzpicture%E3%80%81%E8%B4%B9%E6%9B%BC%E3%80%81%E6%96%B9%E7%A8%8B.png)
我怎样才能将表达式从该图的中心开始放置?表达式有点高,我希望它处于较低且靠近中心的位置。
\documentclass{article}
\usepackage{tikz}
\usepackage[compat=1.0.0]{tikz-feynman}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\begin{tikzpicture}[baseline=(a1.base)]
\large
\begin{feynman}[inline=(a1.base)]
\vertex (a1) {\(d\)};
\vertex[right=2cm of a1] (a2);
\vertex[right=2cm of a2] (a3) {\(s\)};
\vertex[below=4em of a1] (b1) {\(\overline s\)};
\vertex[right=2cm of b1] (b2);
\vertex[right=2cm of b2] (b3) {\(\overline d\)};
\diagram* {
{[edges=fermion]
(a1) -- (a2) -- (a3)
},
{[edges= anti fermion]
(b1) -- (b2) -- (b3)
},
(a2) -- [dashed, edge label=\(Q_i\)] (b2),
};
\end{feynman}
\end{tikzpicture}
\equiv <Q_i>(\alpha_s^0)=Q_i,\\\quad \text{for}\quad Q_i=Q_1,Q_2,E_1,E_2 .
\end{equation}
\end{document}
答案1
我不确定你想要什么。喜欢这个吗?
\documentclass{article}
\usepackage{tikz}
\usepackage[compat=1.0.0]{tikz-feynman}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\begin{tikzpicture}[baseline=(a1.base)]
\large
\begin{feynman}[inline=(a1.base)]
\vertex (a1) {\(d\)};
\vertex[right=2cm of a1] (a2);
\vertex[right=2cm of a2] (a3) {\(s\)};
\vertex[below=4em of a1] (b1) {\(\overline s\)};
\vertex[right=2cm of b1] (b2);
\vertex[right=2cm of b2] (b3) {\(\overline d\)};
\diagram* {
{[edges=fermion]
(a1) -- (a2) -- (a3)
},
{[edges= anti fermion]
(b1) -- (b2) -- (b3)
},
(a2) -- [dashed, edge label=\(Q_i\)] (b2),
};
\end{feynman}
\end{tikzpicture}
\equiv <Q_i>(\alpha_s^0)=Q_i,\\\quad \text{for}\quad Q_i=Q_1,Q_2,E_1,E_2 .
\end{equation}
\end{document}
答案2
您的意思是将方程式置于中心吗?您可以将其设为一个简单的节点,如下所示:
\documentclass{article}
\usepackage{tikz}
\usepackage[compat=1.0.0]{tikz-feynman}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\begin{tikzpicture}[baseline=(a1.base)]
\node at (7,-1) {\( \begin{split}\equiv <Q_i>(\alpha_s^0)=Q_i,\\\quad \text{for}\quad Q_i=Q_1,Q_2,E_1,E_2 \end{split} \)};
\large
\begin{feynman}[inline=(a1.base)]
\vertex (a1) {\(d\)};
\vertex[right=2cm of a1] (a2);
\vertex[right=2cm of a2] (a3) {\(s\)};
\vertex[below=4em of a1] (b1) {\(\overline s\)};
\vertex[right=2cm of b1] (b2);
\vertex[right=2cm of b2] (b3) {\(\overline d\)};
\diagram* {
{[edges=fermion]
(a1) -- (a2) -- (a3)
},
{[edges= anti fermion]
(b1) -- (b2) -- (b3)
},
(a2) -- [dashed, edge label=\(Q_i\)] (b2),
};
\end{feynman}
\end{tikzpicture}
%\equiv <Q_i>(\alpha_s^0)=Q_i,\\\quad \text{for}\quad Q_i=Q_1,Q_2,E_1,E_2 .
\end{equation}
\end{document}