电线伸入 CircuiTikZ 中的欧洲电阻器

Question

我画了一个简单的电路图CircuiTikZ，但我的电线不知怎么地就伸进了电阻器，看起来不太好看。我想这很容易修复，但我做不到。

\documentclass{article}
\usepackage[european,straightvoltages]{circuitikz}

\begin{document}
\begin{circuitikz}
    \draw (0,2) to[open,v=$u_q(t)$] (0,0);
    \draw (0,2) to[short,o-] (1,2);
    \draw (1,2) to[R, l=$R$, v>=$u_R(t)$] (2,2);
    \draw (2,2) -- (3,2);
    \draw (3,2) to[L, l=$L$,v>=$u_{ind}(t)$] (4,2);
    \draw (4,2) -- (5,2);
    \draw (5,2) to[short,i=$i(t)$] (5,0);
    \draw (0,0) to[short,o-] (5,0);
\end{circuitikz}
\end{document}

Answer 1

您正在使用代码将线路过度绘制到“R”组件中

      \draw (0,2) to[short,o-] (1,2);

现在看一下：

\documentclass{article}
\usepackage[european,straightvoltages]{circuitikz}

\begin{document}
\begin{circuitikz}
    \draw (0,2) to[open,v=$u_q(t)$] (0,0);
    \draw (0,2) to[short,o-] (0,2);
    \draw (0,2) to[R, l=$R$, v>=$u_R(t)$] (2,2);
    \draw (2,2) -- (3,2);
    \draw (3,2) to[L, l=$L$,v>=$u_{ind}(t)$] (4,2);
    \draw (4,2) -- (5,2);
    \draw (5,2) to[short,i=$i(t)$] (5,0);
    \draw (0,0) to[short,o-] (5,0);
\end{circuitikz}
\end{document}

通过相对定位你不会出错-- 将产生相同的结果

并避免导线与电感器（“L”）重叠：

\documentclass{article}
\usepackage[european,straightvoltages]{circuitikz}

\begin{document}
\begin{circuitikz}
    \draw (0,2) to [open,v=$u_q(t)$]            (0,0);
    \draw (0,2) to [short,o-]                   ++(0,0)
                to [R, l=$R$, v>=$u_R(t)$]      ++(2,0)
                to [L, l=$L$,v>=$u_{ind}(t)$]   ++(3,0)
                to [short]                      ++(0.5,0)
                to [short,i=$i(t)$]             ++(0,-2)
                to                              (0,0)
                to [short,o-]                   (0,0);
\end{circuitikz}
\end{document}