![我怎样才能在下面的符号表的每个冒号处修复增量符号?](https://linux22.com/image/437363/%E6%88%91%E6%80%8E%E6%A0%B7%E6%89%8D%E8%83%BD%E5%9C%A8%E4%B8%8B%E9%9D%A2%E7%9A%84%E7%AC%A6%E5%8F%B7%E8%A1%A8%E7%9A%84%E6%AF%8F%E4%B8%AA%E5%86%92%E5%8F%B7%E5%A4%84%E4%BF%AE%E5%A4%8D%E5%A2%9E%E9%87%8F%E7%AC%A6%E5%8F%B7%EF%BC%9F.png)
我已经实现了 $|x+1|-|x+2|+|x-3|$ 的符号表,如图所示,但我无法在冒号中修复 delta 符号,例如对于 $|x+1|$,我只想在 $x=-1$ 的冒号处修复 delta 符号,同样,$|x+2|$ 也只能在 $x=-2$ 处修复,而 $|x-3|$ 也只能在 $x=3$ 处修复?我的问题是,我该怎么做?
笔记:我的意思是 delta 符号中的黑点
这是我的代码:
\begin{tikzpicture}
\tkzTabInit[lgt=6,espcl=3,deltacl=0]
{x /.8, $|x+1|$ /.8, $|x+2|$ /.8, $|x-3|$ /.8,$p(x)=|x+1|-|x+2|+|x-3|$/.8}
{$-\infty$,$-2$,$-1$,$3$,$+\infty$} % four main references
\tkzTabLine {,-x-1,t,-x-1,z,x+1,z,x+1} % seven denotations
\tkzTabLine {,-x-2,z,x+2,t,x+2,z,x+2}
\tkzTabLine {,-x+3,z,-x+3,z,-x+3,z,x+3}
\tkzTabLine {,4-x,z,-3x,z,2-x,z,2+x}
\end{tikzpicture}
答案1
像这样吗?
\documentclass{article}
\usepackage{fullpage}
\usepackage{tkz-tab}
\begin{document}
\begin{center}
\begin{tikzpicture}
\tkzTabInit[lgt=6,espcl=3,deltacl=0]
{x /.8, $|x+1|$ /.8, $|x+2|$ /.8, $|x-3|$ /.8,$p(x)=|x+1|-|x+2|+|x-3|$/.8}
{$-\infty$,$-2$,$-1$,$3$,$+\infty$} % four main references
\tkzTabLine {,-x-1,t,-x-1,z,x+1,t,x+1} % seven denotations
\tkzTabLine {,-x-2,z,x+2,t,x+2,t,x+2}
\tkzTabLine {,-x+3,t,-x+3,t,-x+3,z,x-3}
\tkzTabLine {,4-x,t,-3x,t,2-x,t,x-4}
\end{tikzpicture}
\end{center}
\end{document}