TikZ：在节点之间的同一路径上多次着色

Question

-或者因为它只是线条，所以你可以用calc符号计算偏移。当线宽远大于节点边界宽度时，线与圆节点的连接永远不会很好。我通过在背景中绘制线条来避免这种情况。我没有理解你的代码，而是从头开始，只是复制代码，而不是制作相关的样式。

\documentclass[tikz, border=1 cm]{standalone}
\usetikzlibrary{positioning,calc}
\tikzset{aec/.style={circle, draw, inner sep=1pt, minimum size=0.80cm, on grid, fill=white}}
\begin{document}
\pgfdeclarelayer{background}
\pgfsetlayers{background, main}
\begin{tikzpicture}[node distance=0.5 cm and 1.5cm]
\node[aec] (A) {A};
\node[aec, below right=of A] (AB) {\scalebox{0.9}{AB}};
\node[aec, below left=of AB] (B) {B};
\node[aec, below right=of B] (BC) {\scalebox{0.9}{BC}};
\node[aec, below left=of BC] (C) {C};
\node[aec, below right=of C] (CD) {\scalebox{0.9}{CD}};
\node[aec, below left=of CD] (D) {D};
\node[aec, below right=of AB] (ABC) {\scalebox{0.8}{ABC}};
\node[aec, below right=of BC] (BCD) {\scalebox{0.8}{BCD}};
\node[aec, below right=of ABC] (ABCD) {\scalebox{0.7}{ABCD}};
\begin{pgfonlayer}{background}
\draw (A) -- (AB);
\draw (C) -- (BC);
\draw (C) -- (CD);
\draw (D) -- (CD);
\draw[green, line width=3pt] (B.center) -- (AB.center);
\draw[green, line width=3pt] (AB.center) -- (ABC.center);
\draw[red,   line width=3pt] (BC.center) -- (ABC.center);
\draw[blue,  line width=3pt] (BC.center) -- (BCD.center);
\draw[blue,  line width=3pt] (BCD.center) -- (ABCD.center);
\draw[red,   line width=3pt] ($ (B.center)!1.5pt!90:(BC.center) $) -- ($ (BC.center)!1.5pt!-90:(B.center) $);
\draw[blue,  line width=3pt] ($ (B.center)!-1.5pt!90:(BC.center) $) -- ($ (BC.center)!-1.5pt!-90:(B.center) $);
\draw[green, line width=3pt] ($ (ABC.center)!1.5pt!90:(ABCD.center) $) -- ($ (ABCD.center)!1.5pt!-90:(ABC.center) $);
\draw[red,   line width=3pt] ($ (ABC.center)!-1.5pt!90:(ABCD.center) $) -- ($ (ABCD.center)!-1.5pt!-90:(ABC.center) $);
\end{pgfonlayer}
\end{tikzpicture}
\end{document}

为了完全避免这种情况calc，您还可以使用符号进行计算。我会进行坐标移位，而不是画布移位。shift={(\angle:1.5pt)}\angleatan2let

编辑：

节点放置不positioning：

\documentclass[tikz, border=1 cm]{standalone}
\usetikzlibrary{calc}
\def\aev{\dimexpr12pt+0.65cm}
\def\aeh{\dimexpr12pt+1.00cm}
\begin{document}
\begin{tikzpicture}[
  aec/.style={circle,draw,inner sep=1pt,minimum size=0.80cm},
  ]
\coordinate (A) at (0,0);
\coordinate (B) at ([yshift=-\aev] A);
\coordinate (C) at ([yshift=-\aev] B);
\coordinate (D) at ([yshift=-\aev] C);
\coordinate (AB) at ($(A)!0.5!(B)+(\aeh,0)$);
\coordinate (BC) at ($(B)!0.5!(C)+(\aeh,0)$);
\coordinate (CD) at ($(C)!0.5!(D)+(\aeh,0)$);
\coordinate (ABC) at ($(AB)!0.5!(BC)+(\aeh,0)$);
\coordinate (BCD) at ($(BC)!0.5!(CD)+(\aeh,0)$);
\coordinate (ABCD) at ($(ABC)!0.5!(BCD)+(\aeh,0)$);
\foreach \text/\scale in {A/1, B/1, C/1, D/1, AB/2, BC/2, CD/2, ABC/3, BCD/3, ABCD/4}
\node[aec] at (\text) {\scalebox{\ifcase\scale\or1.00\or0.90\or0.80\or0.70\fi}{\text}};
\end{tikzpicture}
\end{document}

positioning有和没有的节点放置calc：

\documentclass[tikz, border=1 cm]{standalone}
\def\aev{\dimexpr12pt+0.65cm}
\def\aeh{\dimexpr12pt+1.00cm}
\begin{document}
\begin{tikzpicture}[
  aec/.style={circle,draw,inner sep=1pt,minimum size=0.80cm},
  ]
\coordinate (A) at (0,0);
\coordinate (B) at ([yshift=-\aev] A);
\coordinate (C) at ([yshift=-\aev] B);
\coordinate (D) at ([yshift=-\aev] C);
\path (A) --coordinate[right=\aeh](AB) (B);
\path (B) --coordinate[right=\aeh](BC) (C);
\path (C) --coordinate[right=\aeh](CD) (D);
\path (AB) --coordinate[right=\aeh](ABC) (BC);
\path (BC) --coordinate[right=\aeh](BCD) (CD);
\path (ABC) --coordinate[right=\aeh](ABCD) (BCD);
\foreach \text/\scale in {A/1, B/1, C/1, D/1, AB/2, BC/2, CD/2, ABC/3, BCD/3, ABCD/4}
\node[aec] at (\text) {\scalebox{\ifcase\scale\or1.00\or0.90\or0.80\or0.70\fi}{\text}};
\end{tikzpicture}
\end{document}

如果节点需要命名，则可以使用例如：

\node[aec] (\text_node) at (\text) {\scalebox{\ifcase\scale\or1.00\or0.90\or0.80\or0.70\fi}{\text}};

对于节点名称(A_node), ...。

Answer 1

您可以使用此答案中的方法：在 TikZ 中绘制额外的平行路径