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Notice that
\begin{align*}
(a_{0}, b_{0}) \equiv (a_{1}, b_{1}) &\hspace{4pt} \text{iff} \quad \text{definition of } \equiv \\
\begin{aligned} a_{0} \neg (a_{0} \wedge b_{0}) &= a_{1} \neg (a_{1} \wedge b_{1}) \text{ and } \\
b_{0} \neg (a_{0} \wedge b_{0}) &= b_{1} \neg (a_{0} \wedge b_{0}) \end{aligned} \bigg\} &\hspace{4pt} \text{iff} \quad \text{using proposition 11.1} \\
\begin{aligned} a_{0} \wedge b_{0}^\prime &= a_{1} \wedge b_{1}^\prime \text{ and } \\ b_{0} \wedge a_{0}^\prime &= b_{1} \wedge a_{1}^\prime \end{aligned} \bigg\} &\hspace{4pt} \text{.}
\end{align*}
The first statement holds.
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有没有更好的方法来对齐这个证明的各个部分?
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align