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我该如何修复我的图表？

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我该如何修复我的图表？

因此，我尝试将此图置于图像中显示的小段落正下方的中心。对于此图，我尝试让两个轴具有相同的缩放比例，但我的域和范围不起作用。出于某种原因，我似乎也无法将图例移动到正确的位置。如果能得到一点帮助，我将不胜感激！

\documentclass{article}
When studying the surface itself, these results cohere with its symmetrical properties; Through projection upon the $xy$plane, the surface's footprint is defined as a two dimensional semi-circle with the equation $y=\sqrt{1-x^2}$ 

\begin{document}
\begin{tikzpicture}
\begin{center}
    
\begin{axis}[
    axis lines = center,
    xlabel = \(x\),
    ylabel = {\(y\)},
]    
%Below the red parabola is defined
\addplot [
    y=-0.25:2,
    domain=-2:2, 
    samples=100, 
    color=red,
]
{(1-x^2)^0.5};
\addlegendentry{\(x^2 - 2x - 1\)}
legend pos: northwest

\end{axis}
\end{center}
\end{tikzpicture}
\end{document}

在此处输入图片描述

答案1

您的环境center位于错误的位置。它必须是完整的图片，而不仅仅是axis环境：

\documentclass{article}
\usepackage{pgfplots}
\pgfplotsset{compat=1.18}
                
\begin{document}
When studying the surface itself, these results cohere with its symmetrical properties; Through projection upon the $xy$plane, the surface's footprint is defined as a two dimensional semi-circle with the equation $y=\sqrt{1-x^2}$

\begin{center}
\begin{tikzpicture}
\begin{axis}[
    axis lines = center,
    xlabel = \(x\),
    ylabel = {\(y\)},
]

%Below the red parabola is defined
\addplot [
    y=-0.25:2,
    domain=-2:2,
    samples=100,
    color=red,
]
{(1-x^2)^0.5};
\addlegendentry{\(x^2 - 2x - 1\)}
legend pos: northwest
\end{axis}
\end{tikzpicture}
\end{center}
\end{document}

在此处输入图片描述

编辑： 轴选项通常收集在它的前导点中，作为图像主体的一部分。因此完整的图像应该是：

\begin{tikzpicture}
\begin{axis}[
    axis lines = center,
    xlabel = \(x\),
    ylabel = {\(y\)},
    enlargelimits=0.2,
    legend pos=north east
]
\addplot [
    domain=-1:1,
    samples=100,
    color=red,
]
{(1-x^2)^0.5};
\legend{\(x^2 - 2x - 1\)}
\end{axis}
\end{tikzpicture}

在此处输入图片描述

figure但是，您可以按如下方式将图像插入浮动环境中：

\documentclass{article}
\usepackage{pgfplots}
\pgfplotsset{compat=1.18}
                
\begin{document}
When studying the surface itself, these results cohere with its symmetrical properties; Through projection upon the $xy$plane, the surface's footprint is defined as a two dimensional semi-circle with the equation $y=\sqrt{1-x^2}$

\begin{figure}[ht]
\centering
\begin{tikzpicture}
\begin{axis}
...
\end{axis}
\end{tikzpicture}
\end{figure}
\caption{My image}
\label{fig:ilustration}
\end{document}

在此处输入图片描述

答案2

您需要放置您的tikzpicture内部figure环境。

就这样

\begin{figure}[h]
\begin{center}
    \begin{tikzpicture}[scale=2]
        \draw[help lines] (0,0) grid (2,3);
        \draw[<->] (0,3.1) -- (0,0) -- (2.1,0);
        \draw[green,fill=yellow] (1,1) circle [radius=0.5];
        \draw[red] (0,0) -- (0,1);
        \draw[red] (0,1) -- (1,1) -- (2,3);
        \draw[domain=-1:2] plot (\x, \x*\x + 2);
        \node[below] at (1,1) {\tiny Text $R=0,5$};
    \end{tikzpicture}
    \caption{TikZ centered}
\end{center}
\end{figure}

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