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水平排列分子

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水平排列分子

我试图让两个反应中的加号与方程中的箭头和其他加号对齐。我尝试重新排列 \arrow{0}[,0] 看看是否有什么变化，不过现在我有点不知所措了。

\documentclass{article}
\usepackage{graphicx}
\usepackage{chemfig}
\usepackage{geometry}
\usepackage{tabu}
\usepackage{textgreek}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usepackage{siunitx}
\usepackage{chemmacros}
\usetikzlibrary{arrows}

\begin{document}
\vspace{2mm}
\begin{center}
\tabulinesep = ^ 4mm _ 4mm % border gap
\begin{tabu} to 13cm {|X[cm]|}
    \hline
    \schemestart
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]O-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]}
    \arrow{0}[,0]
    \+
    \chemfig{-[:30,0.75]-[:-30,0.75]OH}
    \arrow[,1.1,thick]
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]O-[:30,0.75]-[:-30,0.75]}
    \arrow{0}[,0]
    \+ 
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]OH}
    \schemestop
    \\
    \hline
\end{tabu}
\end{center}

\vspace{2mm}
\begin{center}
\tabulinesep = ^ 4mm _ 4mm % border gap
\begin{tabu} to 13cm {|X[cm]|}
    \hline
    \schemestart
    \chemfig{-[:30](=[:90,0.75]O)-[:-30,0.75]OH}
    \arrow{0}[,0]
    \+
    \chemfig{-[:30](=[:90,0.75]O)-[:-30,0.75]OH}
    \arrow[,1.5,thick]
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30]O-[:30](=[:90,0.75]O)-[:-30,0.75]}
    \arrow{0}[,0]
    \+ 
    \chemfig{H_2O}
    \schemestop
    \\
    \hline
\end{tabu}
\end{center}

\end{document}

答案1

问题可能在于分子的书写方式

\begin{center}
\tabulinesep = ^ 4mm _ 4mm % border gap
\begin{tabu} to 16cm {|X[cm]|}
    \hline
\schemestart
%
\chemfig{(-[:210])(=[2]O)-[:330]O-[:30](=[2]O)-[:330]}
%
\+
%
\chemfig{-[:30]-[:330]OH}
%
\arrow{->}
%
\chemfig{(-[:210])(=[2]O)-[:330]O-[:30]-[:330]}
%
\+
%
\chemfig{(-[:210])(=[2]O)-[:330]OH}
\schemestop 
\\
\hline
\end{tabu}
\end{center}    
    
\vspace{1cm}

\begin{center}
    \tabulinesep = ^ 4mm _ 4mm % border gap
    \begin{tabu} to 16cm {|X[cm]|}
        \hline
        \schemestart
        %
        \chemfig{(-[:210])(=[2]O)-[:330]OH}
        %
        \+
        %
        \chemfig{(-[:210])(=[2]O)-[:330]OH}
        %
        \arrow{->}
        %
        \chemfig{(-[:210])(=[2]O)-[:330]O-[:30](=[2]O)-[:330]}
        %
        \+
        %
        \chemfig{(-[:210])(=[2]O)-[:330]OH}
        \schemestop 
        \\
        \hline
    \end{tabu}
\end{center}

在此处输入图片描述

答案2

这是一个可能的解决方案，也使用\arrow{0}[,0]为了将所有分子垂直居中，以及一个反应内的加号和箭头。我还用tabu一种基础方法替换了反应方案周围的基础框架tcolorbox。由于第二种方案中的乙酸和乙酸酐分子由于键长不同而看起来相当扭曲，我添加了一个替代版本，不需要手动调整每个键长：

在此处输入图片描述

\documentclass{article}
\usepackage{chemfig}
\usepackage{geometry}
\usepackage{tcolorbox}

\newtcolorbox{mybox}{colback=white,colframe=black,sharp corners, halign=center, boxrule=\arrayrulewidth}

\begin{document}

\begin{mybox}
    \schemestart
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]O-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]}
    \arrow{0}[,0]
    \+
    \chemfig{-[:30,0.75]-[:-30,0.75]OH}
    \arrow[,1.1,thick]
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]O-[:30,0.75]-[:-30,0.75]}
    \arrow{0}[,0]
    \+ 
    \arrow{0}[,0]
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30,0.75]OH}
    \schemestop
\end{mybox}

\smallskip

\begin{mybox}
    \schemestart
    \arrow{0}[,0]
    \chemfig{-[:30](=[:90,0.75]O)-[:-30,0.75]OH}
    \arrow{0}[,0]
    \+
    \arrow{0}[,0]
    \chemfig{-[:30](=[:90,0.75]O)-[:-30,0.75]OH}
    \arrow[,1.5,thick]
    \chemfig{-[:30,0.75](=[:90,0.75]O)-[:-30]O-[:30](=[:90,0.75]O)-[:-30,0.75]}
    \arrow{0}[,0]
    \+ 
    \chemfig{H_2O}
    \schemestop
\end{mybox}

\bigskip

\setchemfig{atom sep=2.5em}
\begin{mybox}
    \schemestart
    \chemfig{-[:30](=[:90]O)-[:-30]O-[:30](=[:90]O)-[:-30]}
    \arrow{0}[,0]
    \+
    \chemfig{-[:30]-[:-30]OH}
    \arrow[,1.1,thick]
    \chemfig{-[:30](=[:90]O)-[:-30]O-[:30]-[:-30]}
    \arrow{0}[,0]
    \+ 
    \arrow{0}[,0]
    \chemfig{-[:30](=[:90]O)-[:-30]OH}
    \schemestop
\end{mybox}

\smallskip

\begin{mybox}
    \schemestart
    \arrow{0}[,0]
    \chemfig{-[:30](=[:90]O)-[:-30]OH}
    \arrow{0}[,0]
    \+
    \arrow{0}[,0]
    \chemfig{-[:30](=[:90]O)-[:-30]OH}
    \arrow[,1.5,thick]
    \chemfig{-[:30](=[:90]O)-[:-30]O-[:30](=[:90]O)-[:-30]}
    \arrow{0}[,0]
    \+ 
    \chemfig{H_2O}
    \schemestop
\end{mybox}

\end{document}

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