PGF 中的刻度格式，如何切换到完全十进制而不使用 10 的幂

Question

刻度彼此紧贴，几乎重叠。如何在不改变图表尺寸的情况下将刻度从 $2.5\cdot 10^{-2}$ 更改为仅 $0.025$？

\begin{tikzpicture}
\pgfplotsset{width={.5\textwidth},height={6 cm}}
\begin{axis}[ylabel={$\ln (I/I_0)$},
grid=major,
legend style={ legend pos= north east,},
xtick distance= .025,
]
\addplot[red, mark=square, only marks,]coordinates{
(0., 0.) (0.025, -0.842) (0.05, -1.671) (0.075, -2.217) (0.1, -2.823)};
\legend{$\theta = 11.0^\circ$; $\lambda = 0.77$ pm}
\end{axis}
\end{tikzpicture}

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评论后

Answer 1

尝试这个：

\documentclass[border=1mm]{standalone}
\usepackage{pgfplots}

\begin{document}

\begin{tikzpicture}
\pgfplotsset{width={.5\textwidth},height={6 cm}}
\begin{axis}[ylabel={$\ln (I/I_0)$},
grid=major,
legend style={legend pos=north east},
xtick distance=.025,
xticklabel style={/pgf/number format/fixed, /pgf/number format/precision=3}
]
\addplot[red, mark=square, only marks,]coordinates{
(0., 0.) (0.025, -0.842) (0.05, -1.671) (0.075, -2.217) (0.1, -2.823)};
\legend{$\theta = 11.0^\circ$; $\lambda = 0.77$ pm}
\end{axis}
\end{tikzpicture}

\end{document}