博弈论表

博弈论表

我想在 latex 中重现这些表格。
不幸的是,当我要写它们时,它们很糟糕。
它们是代表博弈论案例的表格。

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这是我针对第一个问题提出的暂定解决方案:

\begin{table}[]
\begin{tabular}{|l|l|l|l|}
\hline
Pilot              & Move & Performance   & Cost   \\ \hline
\multirow{3}{*}{A} & 1    & $eq_{1} = 42$ & \Delta t_{p} = 2  \\ \cline{2-4} 
                   & 2    & $eq_{2} = 44$ & 2\Delta t_{p} = 4 \\ \cline{2-4} 
                   & 3    & $eq_{3} = 42$ & \Delta t_{p} = 2  \\ \hline
\multirow{3}{*}{B} & 1    & $eq_{1} = 42$ & \Delta t_{p} = 2  \\ \cline{2-4} 
                   & 2    & $eq_{2} = 44$ & 2\Delta t_{p} = 4 \\ \cline{2-4} 
                   & 3    & $eq_{3} = 42$ & \Delta t_{p} = 2  \\ \hline
\end{tabular}
\end{table}

答案1

这是针对您的第一张表的解决方案。它使用了tabularray非常适合这种表的包。

\documentclass{article}
\usepackage{tabularray}
\newcommand{\lbf}{\large\bfseries}

\begin{document}
\begin{table}
\begin{tblr}{colspec={|c|c|c|c|},hlines,
    cell{2}{1}={r=2}{font=\lbf},cell{4}{1}={r=2}{font=\lbf}}
Player & Action            & Cost      & Effectiveness \\ \hline
 S     & D (detailed scan) & $c_D = 2$ & $ b_D = 1 $    \\
       & Q (quick scan)    & $c_Q = 1$ & $ b_Q = 1 $    \\  
 A     & F (fast mode)     & $c_F = 1$ & $ b_F = -1 $   \\
       & C (cautious mode) & $c_C = 2$ & $ b_C = 1 $    \\  
\end{tblr}
\end{table}

\end{document}

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答案2

第一个(@Pieter van Oostrum 不错的答案的一点点变化,+1)和第二个表格:

\documentclass{article}
\usepackage[skip=1ex, font=small, labelfont=bf]{caption}
\usepackage{tabularray}
\newcommand{\lbf}{\large\bfseries}

\begin{document}
\begin{table}[ht]
    \centering
\caption{First table}
\begin{tblr}{hlines, vlines,
             colspec={c l *{2}{Q[l, mode=math]}},
             cell{2}{1}={r=2}{font=\lbf},
             cell{4}{1}={r=2}{font=\lbf},
             row{1} = {mode=text, c}
             }
Player & Action            & Cost      & Effectiveness \\ 
    \hline
 S     & D (detailed scan) & c_D = 2 &  b_D = 1     \\
       & Q (quick scan)    & c_Q = 1 &  b_Q = 1     \\
 A     & F (fast mode)     & c_F = 1 &  b_F = -1    \\
       & C (cautious mode) & c_C = 2 &  b_C = 1     \\
\end{tblr}
\end{table}

\begin{table}[ht]
    \centering
\caption{Second table}
\begin{tblr}{hline{3-Z}=solid, vline{3-Z}=solid,
             colspec={c c *{2}{Q[l, mode=math]}},
              row{1-2} = {mode=text, c}
             }
\SetCell[c=2, r=2]{c}
    &   &   \SetCell[c=2]{c}    Player A
                                &                       \\
    &   &           F           &       C               \\
\SetCell[r=4]{c}    Player S
    &\SetCell[r=2]{c}  D 
        & P_{r_n} - c_D + b_D   & P_{r_c} - c_D + b_D   \\
    &   & P_{r_n} - c_F + b_D   & P_{r_c} - c_C + b_C   \\
    &\SetCell[r=2]{c}  Q
        & P_{r_n} - c_Q + b_D   & P_{r_c} - c_Q + b_Q   \\
    &   & P_{r_n} - c_F + b_D   & P_{r_c} - c_C + b_C   \\
\end{tblr}
\end{table}

\end{document}

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