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Tikz，装饰库

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Tikz，装饰库

我如何重新定义下面 MWE 中的小于不等式，以使其类似于屏幕截图所示的不等式？

在此处输入图片描述

这是使用的代码。

\begin{tikzpicture}[scale=0.7]
    % Draw the grid
    \tikzset{help lines/.style={color=blue!50}}
    \draw[thick,step=1cm,help lines] (0,0) grid (20,13);
    \draw[thin,step=2mm,help lines] (0,0) grid (20,13);
    \begin{axis}[thick,
        axis x line=center,  axis y line=center,
        axis on top,
        width=16cm,           height=16cm,
        x axis line style={latex-latex},
        y axis line style={latex-latex},
        x=1cm,
        y=1cm,
        xtick={0,1,2,...,18},
        ytick={0,1,2,...,12},
        ticklabel style={font={{\normalsize }}, fill=white,
            inner sep=1pt},
        xmin=-2,   xmax=18.5,
        ymin=-1,   ymax=12.5
        ]
        %line one
        \addplot [IneqStyleGtr,
        domain=-1:18,line width=1.5pt,
        ] {-4*x+24};
        %line two
        \addplot [IneqStyleGtr,line width=1.5pt,
        domain=-1:15,
        ] {-1.3333333333*x+10.666666666667};
        %line three - y axis
        \addplot [IneqStyleLess,
        thick,black!80!white,domain=-1:18,line width=1.5pt] coordinates {(0,0) (18,0)};
            \addplot [IneqStyleGtr,
        thick,black!80!white,domain=-1:18,line width=1.5pt] coordinates {(0,0) (0,12)};
        %line 4 x axis
        \addplot [IneqStyleGtr,
        thick,black!80!white,domain=-1:16,line width=1.5pt] {-0.5*x+9};
        
        
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:18,0.2) {$x$-axis};
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:0.6,12) {$y$};
        %line one
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:11,0.2) {$y=0$};
        
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:4.2,11.3) {$4x+y=24$};
        %line two
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:13.5,3) {$x+2y=18$};
        %line three
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:8.5,1) {$4x+3y=32$};
        %line four
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:-1,6) {$x=0$};
        
        %ORIGIN
        \node[fill=white,rounded corners=2pt,inner sep=1pt] at (axis cs:-0.2,-0.2) {$0$};
    \end{axis}
\end{tikzpicture}

答案1

  • 请始终提供 MWE（最小工作示例），这是一个完整的小型可编译文档，它可以重现您的问题并显示您在解决问题时遇到的问题。
  • 你的问题不太清楚，你的问题是什么？你的代码片段包含未定义的命令，也与显示的图像不接近，所以我猜你在做什么。
  • 像这样吗？

在此处输入图片描述

\documentclass[margin=3mm]{standalone}
\usepackage{pgfplots}
\pgfplotsset{compat=1.18}
\usepgfplotslibrary{fillbetween} 
\usetikzlibrary{intersections,
                patterns}


\begin{document}
    \begin{tikzpicture}[scale=0.5,
lbl/.style = {#1, near end, font=\small, sloped} % #1: position
                        ]
   \begin{axis}[
    axis lines=center, semithick,
    x=10mm, y=10mm,
    xlabel=$x$,
    ylabel=$y$,
    label style = {font=\Large},
grid=both, minor tick num=9,
major grid style = {blue!30},    
minor grid style = {very thin,  blue!15},    
    ticklabel style={rounded corners, font=\scriptsize, fill=white, inner sep=1pt},
        xmin=-10,  xmax=10,  xtick={-10,-9,...,10},
        ymin=-10,  ymax=10,  ytick={-10,-9,...,10},
%
every axis plot post/.append style={thick, color=black},
    domain = -10:10, no marks
                ]
        %line one
\addplot[name path=A]   {x} node[lbl=above] {$y>x$}
                            node[lbl=below] {$y<x$};
\path   [name path=B] (-10,10) -- (-10,10);

\addplot[pattern=north west lines, 
         distance=2.82mm,
         pattern color=orange!50]
         fill between[of=A and B];
\end{axis}
    \end{tikzpicture}
\end{document}

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