scalebox 中的支撑厚度相同

Question

\documentclass[14pt]{extarticle}
\usepackage{graphicx}

\begin{document}
\begin{equation}
\scalebox{0.5}[1]{$\displaystyle
\left\{\scalebox{2}[1]{$\displaystyle\begin{array}{ll}
P=P(r_+,M)\\
T=T(r_+,P(r_+,M)),
\end{array}$}\right.$}
\end{equation}
\begin{equation}
\scalebox{0.5}[1]{$\displaystyle
\left\{\scalebox{2}[1]{$\displaystyle\begin{array}{ll}
\bigg(\displaystyle\frac{\partial P}{\partial V}\bigg)_{T,Q_e}\bigg|_{V_c,T_c}=0\\
\bigg(\displaystyle\frac{\partial^2P}{\partial V^2}\bigg)_{T,Q_e}\bigg|_{V_c,T_c}=0.
\end{array}$}\right.$}
\end{equation}
\begin{equation}
A+\bigg(\bigg(\bigg(\frac{B}{C}+\frac{B}{C}\bigg)\bigg)\bigg)
\end{equation}
\end{document}

我想像 那样计算支架厚度(1)。(2)此外，也许有更好的方法来表示此类公式(1)-(3)。

Answer 1

这个解决方案和这个包怎么样empheq？

     \documentclass[14pt]{extarticle}
    \usepackage{graphicx}
    \usepackage{empheq}
    \usepackage{diffcoeff}

    \begin{document}

    \begin{empheq}[left=\empheqlbrace]{equation}
    \begin{aligned}
    P & =P(r_+,M)\\
    T & =T(r_+,P(r_+,M)),
    \end{aligned}
    \end{empheq}
    \begin{empheq}[left=\enspace \empheqlbrace]{equation}
    \begin{aligned}
    \biggl(\diffp{P}{V}[T,Q_e]\biggm|_{V_c,T_c} & =0\\
    \bigg(\diffp[2]{P}{V}[T,Q_e]\biggm|_{V_c,T_c} & =0.
    \end{aligned}
    \end{empheq}
    \begin{equation}
    \quad A+\biggl(\biggl(\biggl(\frac{B}{C}+\frac{B}{C}\biggr)\biggr)\biggr)
    \end{equation}

    \end{document}