如何获取伪代码中对应行的正确数字？

Question

\begin{algorithm}
\caption{Random Vector Generation}
\begin{algorithmic}
\State Generate $\mathit{n}$ random variables $\mathit{U_{1},...,U_{n}}$ as iid variables from $\mathit{U(0,1)}$ \newline
\State Set $X_{1} = 1- X_{n},...,X_{n} = 1- 2U_{n}$ and $\mathit{R = \sum_{i=1}^n X_{i}^2}$ \newline
\State if $\mathit{R \leq 1}$, accept $\mathit{\textbf{X} = (X_{1},....X_{n})^T}$ as the desired vector; otherwise go to step 1.
\end{algorithmic}
\end{algorithm}

Answer 1

我不知道你是怎么得到那张照片的，因为电话

\begin{algorithmic}

相当于

\begin{algorithmic}[0]

意思是“没有行号”。你想要

\begin{algorithmic}[1]

意思是“给每行编号”。

这是有效的代码，使用了更好的技巧来\newline分隔线条。

\documentclass{article}
\usepackage{algorithm,algpseudocode}

\begin{document}

\begin{algorithm}
\caption{Random Vector Generation}
\begin{algorithmic}[1]
\setlength{\itemsep}{1ex}
\State Generate $n$ random variables $U_{1},\dots,U_{n}$ as iid variables from
       $U(0,1)$
\State Set $X_{1} = 1- 2U_{1},\dots,X_{n} = 1- 2U_{n}$ and $R = \sum_{i=1}^n X_{i}^2$
\State if $R \leq 1$, accept $\mathbf{X} = (X_{1},\dots,X_{n})^T$ as the desired vector;
       otherwise go to step~1.
\end{algorithmic}
\end{algorithm}

\end{document}

请注意，我删除了所有\mathit声明并将其转换...为\dots。我还修复了X_{1}=1-2U_{1}。