我想在两个向量之间画一个角度:
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{angles,quotes,babel,plotmarks}
\usetikzlibrary{decorations.pathreplacing}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}[decoration=brace]
% orthogonal ground line
\draw[thick] (-3,0) -- (3,0);
% Origin
\draw[fill=black] (0,0) node(O)[anchor=north] {$O$};
% vector a
\draw[thick,->] (0,0) -- (-2,2) node(a)[anchor=north east] {$a$};
% vector b
\draw[thick,->] (0,0) -- (2.5,1.5) node(b)[anchor=west] {$b$};
\pic [draw, -, angle eccentricity=1.2, angle radius=1cm,, "$\gamma$"] {angle=b--O--a};
\end{tikzpicture}
\end{document}
由于某些原因,绘制的角度比预期的要大?
有什么建议关于如何正确做到这一点?
答案1
原因是您错误地定义了角度的坐标。如果您写入\draw (0,0) -- (-2,2) node (a) [anchor=north east] {$a$};
,则您将 定义(a)
为对标签 的节点的引用$a$
,其中心(如您所定义)north east
为 坐标(-2,2)
。但这(-2,2)
实际上是您所需的角度坐标。
因此,你应该这样做:
\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{angles,quotes}
\begin{document}
\begin{tikzpicture}
% orthogonal ground line
\draw[thick] (-3,0) -- (3,0);
% Origin
\draw[fill=black] (0,0) coordinate (O) node [anchor=north] {$O$};
% vector a
\draw[thick,->] (0,0) -- (-2,2) coordinate (a) node[anchor=north east] {$a$};
% vector b
\draw[thick,->] (0,0) -- (2.5,1.5) coordinate (b) node[anchor=west] {$b$};
\pic[draw, angle eccentricity=1.2, angle radius=1cm,, "$\gamma$"] {angle=b--O--a};
\end{tikzpicture}
\end{document}
或者,您可以使用labels
:
\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{angles,quotes}
\begin{document}
\begin{tikzpicture}
% orthogonal ground line
\draw[thick] (-3,0) -- (3,0);
% Origin
\draw[fill=black] (0,0) coordinate[label={below:$0$}] (O);
% vector a
\draw[thick,->] (0,0) -- (-2,2) coordinate[label={below left:$a$}] (a);
% vector b
\draw[thick,->] (0,0) -- (2.5,1.5) coordinate[label={right:$b$}] (b);
\pic [draw, angle eccentricity=1.2, angle radius=1cm,, "$\gamma$"] {angle=b--O--a};
\end{tikzpicture}
\end{document}
答案2
这很容易做到pstricks
– 更具体地说是pst-eucl
:
\documentclass[pstricks, border=6pt]{standalone}
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}(-3,-1)(3,3)
\psset{arrowinset=0.12,labelsep=3pt}
\pstGeonode[PointSymbol=none, PosAngle={-90,135, 45}](0,0){O}(-2,2){a}(2.5,1.5){b}
% orthogonal ground line
\psline (-3,0)(3,0)
\ncline{->}{O}{a}\ncline{->}{O}{b}
\pstMarkAngle[linewidth=0.3pt, LabelSep=0.6]{b}{O}{a}{$\gamma$}%
\end{pspicture}
\end{document}
答案3
节点不在端点,而是在其他地方,你需要像这样指定坐标
\begin{tikzpicture}[decoration=brace]
% orthogonal ground line
\draw[thick] (-3,0) -- (3,0);
% Origin
\coordinate (O) at (0,0);
\draw[fill=black] (O) node[anchor=north] {$O$};
% vector a
\coordinate (a) at (-2,2);
\draw[thick,->] (O) -- (a) node[anchor=south east] {$a$};
% vector b
\coordinate (b) at (2.5,1.5);
\draw[thick,->] (O) -- (b) node[anchor=south west] {$b$};
\pic [draw, -, angle eccentricity=1.2, angle radius=1cm,, "$\gamma$"] {angle=b--O--a};
\end{tikzpicture}