我希望获得以下输出，但下面给出的代码产生了不同的输出。
这是我的代码。
\documentclass[10pt,journal,compsoc]{IEEEtran}
\usepackage{algorithm}
\usepackage{algpseudocode}
\begin{document}
\begin{algorithm}
\caption{This is Algo. 1}
\textbf{Input: } The . \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here.....
\end{algorithmic}
\end{algorithm}
\floatname{algorithm}{Procedure}
\begin{algorithm}
\caption{\textproc This is procedure 1 }
\textbf{Input: } The. \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here....
\end{algorithmic}
\end{algorithm}
\begin{algorithm}
\caption{This is procedure 2}
\textbf{Input: } The. \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here....
\end{algorithmic}
\end{algorithm}
\begin{algorithm}
\caption{This is Algo. 2}
\textbf{Input: } The. \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here .....
\end{algorithmic}
\end{algorithm}
\end{document}
答案1
procedure您可以通过定义一个新的计数器来完成这项工作，尝试以下代码：
\documentclass[10pt,journal,compsoc]{IEEEtran}
\usepackage{algorithm}
\usepackage{algpseudocode}
\newcounter{procedure}
\makeatletter
\newenvironment{procedure}[1][htb]{%
\let\c@algorithm\c@procedure
\renewcommand{\ALG@name}{Procedure}% Update algorithm name
\begin{algorithm}[#1]%
}{\end{algorithm}
}
\makeatother
\begin{document}
\begin{algorithm}
\caption{This is Algo. 1}
\textbf{Input: } The . \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here.....
\end{algorithmic}
\end{algorithm}
\begin{procedure}
\caption{\textproc This is procedure 1 }
\textbf{Input: } The. \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here....
\end{algorithmic}
\end{procedure}
\begin{procedure}
\caption{This is procedure 2}
\textbf{Input: } The. \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here....
\end{algorithmic}
\end{procedure}
\begin{algorithm}
\caption{This is Algo. 2}
\textbf{Input: } The. \\
\textbf{Output: } .
\begin{algorithmic}[1]
\State Here .....
\end{algorithmic}
\end{algorithm}
\end{document}
改编自这个答案。
