对于在演示文稿中提出多项选择题，我想定义一些有助于突出显示答案的命令。答案可能应该跨越多行。
为此，目前一个可行的解决方案如下：
\documentclass[compress,aspectratio=169,12pt]{beamer}
\usepackage[utf8]{inputenc}
\newcommand{\correctAnswer}[1]{ \colorbox{green}{
\hspace{-0.6cm}
\begin{minipage}[t]{13cm}
\hspace{0.3cm}
#1
\end{minipage}
} }
\newcommand{\wrongAnswer}[1]{ \colorbox{red}{
\hspace{-0.6cm}
\begin{minipage}[t]{13cm}
\hspace{0.3cm}
#1
\end{minipage}
} }
\newcommand{\unknownAnswer}[1]{ \colorbox{white}{
\hspace{-0.6cm}
\begin{minipage}[t]{13cm}
\hspace{0.3cm}
#1
\end{minipage}
} }
\newcommand{\correctAnswerBlock}[1]{\alt<2>
{\unknownAnswer{#1}}
{\correctAnswer{#1}}
}
\newcommand{\wrongAnswerBlock}[1]{\alt<2>
{\unknownAnswer{#1}}
{\wrongAnswer{#1}}
}
\begin{document}
\begin{frame}[fragile]{Questions}
\begin{onlyenv}<1>
\begin{itemize}
\item Are there questions from your side?
\end{itemize}
\end{onlyenv}
\begin{onlyenv}<2-3>
What is true regarding reductions?
\begin{enumerate}
\item \wrongAnswerBlock{If we can reduce a Problem $C$ to problem $D$ by a polynomial \par \hspace{0.3cm} algorithm $A_T$ ($C \leq_p D$), than both problems are in $\mathcal{P}$.}
\item \wrongAnswerBlock{If we can reduce a Problem $D$ to problem $C$ by a polynomial \par \hspace{0.3cm} algorithm $A_T$ ($D \leq_p C$), than both problems are in $\mathcal{P}$.}
\item \wrongAnswerBlock{Given a reduction $A_T$ of a problem $C$ to a problem $D$ ($C \leq_p D$), \par \hspace{0.3cm} we know that iff input $\alpha \in D$, than $A_T(\alpha) \in C$.}
\item \correctAnswerBlock{Given a reduction $A_T$ of a problem $C$ to a problem $D$ ($C \leq_p D$), \par \hspace{0.3cm} we know that iff input $\alpha \in C$, than $A_T(\alpha) \in D$.}
\end{enumerate}
\end{onlyenv}
\end{frame}
\end{document}
这会产生正确的输出：
不幸的是，它要求\par \hspace{0.3cm}为每个换行符添加，否则，minipage换行符会太靠左。不幸的是，添加负数hspace是必要的，否则，colorbox会插入一些空格：
此外，添加负面vspace（或\hspace*，如建议的那样迷你页面内没有水平间距) 并没有解决问题。
或者，也可以使用tcbox：
\usepackage{tcolorbox}
\usepackage{varwidth}
\tcbset{colframe=white,
colback=white,
coltext=black,
varwidth upper}
\newcommand{\correctAnswer}[1]{ \tcbox[colback=green, left=0cm, top=0cm, bottom=0cm]{#1} }
\newcommand{\wrongAnswer}[1]{ \tcbox[colback=red, left=0cm, top=0cm, bottom=0cm]{#1} }
\newcommand{\unknownAnswer}[1]{ \tcbox[colback=white, left=0cm, top=0cm, bottom=0cm]{#1}}
这是可行的，但是会破坏项目的对齐：
设置boxsep（例如在 tcolorbox 中设置行距）等参数并没有改变对齐的问题，而且halign和valign属性似乎都没有改变anchor。
即使经过一段时间的折腾，我还是找不到解决方案（除了\par \hspace{-0.6cm}解决方案，但不是很好）。有没有解决方案可以让我的文本周围出现一个彩色框，并在枚举内正确对齐？
答案1
您无需手动调整间距，而是可以更改\fboxsep：
\documentclass[compress,aspectratio=169,12pt]{beamer}
\usepackage[utf8]{inputenc}
\setlength{\fboxsep}{0.3cm}
\newcommand{\correctAnswer}[1]{\colorbox{green}{%
\begin{minipage}[t]{\dimexpr\linewidth-2\fboxsep}
#1
\end{minipage}%
}}
\newcommand{\wrongAnswer}[1]{\colorbox{red}{%
\begin{minipage}[t]{\dimexpr\linewidth-2\fboxsep}
#1
\end{minipage}%
}}
\newcommand{\unknownAnswer}[1]{\colorbox{white}{%
\begin{minipage}[t]{\dimexpr\linewidth-2\fboxsep}
#1
\end{minipage}%
}}
\newcommand{\correctAnswerBlock}[1]{\alt<2>
{\unknownAnswer{#1}}
{\correctAnswer{#1}}
}
\newcommand{\wrongAnswerBlock}[1]{\alt<2>
{\unknownAnswer{#1}}
{\wrongAnswer{#1}}
}
\begin{document}
\begin{frame}[fragile]{Questions}
\begin{onlyenv}<1>
\begin{itemize}
\item Are there questions from your side?
\end{itemize}
\end{onlyenv}
\begin{onlyenv}<2-3>
What is true regarding reductions?
\begin{enumerate}
\item \wrongAnswerBlock{If we can reduce a Problem $C$ to problem $D$ by a polynomial \par algorithm $A_T$ ($C \leq_p D$), than both problems are in $\mathcal{P}$.}
\item \wrongAnswerBlock{If we can reduce a Problem $D$ to problem $C$ by a polynomial \par algorithm $A_T$ ($D \leq_p C$), than both problems are in $\mathcal{P}$.}
\item \wrongAnswerBlock{Given a reduction $A_T$ of a problem $C$ to a problem $D$ ($C \leq_p D$), \par we know that iff input $\alpha \in D$, than $A_T(\alpha) \in C$.}
\item \correctAnswerBlock{Given a reduction $A_T$ of a problem $C$ to a problem $D$ ($C \leq_p D$), \par we know that iff input $\alpha \in C$, than $A_T(\alpha) \in D$.}
\end{enumerate}
\end{onlyenv}
\end{frame}
\end{document}
答案2
我不会\tcbox为此使用 a。如果你改用 a tcolorbox，则所有项目都会具有相同的宽度，并且你不必手动强制换行：
\documentclass[compress,aspectratio=169,12pt]{beamer}
\usepackage[most]{tcolorbox}
\tcbset{
colframe=white,
colback=white,
coltext=black,
}
\newtcolorbox{answerbox}[1][]{left=0.3cm, right=0.3cm, top=0cm, bottom=0cm,box align=top,nobeforeafter,before skip=0pt,#1,ignore nobreak}
\colorlet{wrongcol}{red}
\colorlet{correctcol}{green}
\newcommand{\correctAnswer}[1]{%
\only<2>{\colorlet{correctcol}{white}}%
\raisebox{.87\baselineskip}{\begin{answerbox}[colback=correctcol]
#1
\end{answerbox}}%
}
\newcommand{\wrongAnswer}[1]{%
\only<2>{\colorlet{wrongcol}{white}}%
\raisebox{.87\baselineskip}{\begin{answerbox}[colback=wrongcol]
#1
\end{answerbox}}%
}
\newcommand{\unknownAnswer}[1]{%
\raisebox{.87\baselineskip}{\begin{answerbox}[colback=white]
#1
\end{answerbox}}%
}
\begin{document}
\begin{frame}[fragile]{Questions}
\begin{onlyenv}<1>
\begin{itemize}
\item Are there questions from your side?
\end{itemize}
\end{onlyenv}
\begin{onlyenv}<2-3>
What is true regarding reductions?
\begin{enumerate}
\item \wrongAnswer{If we can reduce a Problem $C$ to problem $D$ by a polynomial algorithm $A_T$ ($C \leq_p D$), than both problems are in $\mathcal{P}$.}
\item \wrongAnswer{If we can reduce a Problem $D$ to problem $C$ by a polynomial algorithm $A_T$ ($D \leq_p C$), than both problems are in $\mathcal{P}$.}
\item \wrongAnswer{Given a reduction $A_T$ of a problem $C$ to a problem $D$ ($C \leq_p D$), we know that iff input $\alpha \in D$, than $A_T(\alpha) \in C$.}
\item \correctAnswer{Given a reduction $A_T$ of a problem $C$ to a problem $D$ ($C \leq_p D$), we know that iff input $\alpha \in C$, than $A_T(\alpha) \in D$.}
\end{enumerate}
\end{onlyenv}
\end{frame}
\end{document}
