GCD我创建了一个在和之间切换的命令LCM。但是，它有一个副作用，就是删除命令后第二个可见字符之前的所有内容。我该如何修复这个错误？
\documentclass{article}
\newcommand{\GCDorLCM}[2]{\ifcase#1 GCD\or LCM\fi}
\newenvironment{GCDLCM_A}[3]{Find the \GCDorLCM{#1} of {#2} and {#3}.}{}
\newenvironment{GCDLCM_B}[2]{\GCDorLCM{#1} is maximized when \(x={#2}\).}{}
\title{}
\author{}
\begin{document}
\begin{GCDLCM_A}{1}{120}{84}
\end{GCDLCM_A}
\begin{GCDLCM_B}{0}{75}
\end{GCDLCM_B}
\end{document}
预期输出：
Find the LCM of 120 and 84.
GCD is maximized when x = 75.
实际产量：
Find the LCMf 120 and 84.
GCDs maximized when x = 75.
答案1
与\ifcase您无关\newcommand{\GCDorLCM}[2]，因此用两个参数定义它，但您只使用#1因此#2（在o这里）被丢弃。
\documentclass{article}
\newcommand{\GCDorLCM}[1]{\ifcase#1 GCD\or LCM\fi}
\newenvironment{GCDLCM_A}[3]{Find the \GCDorLCM{#1} of {#2} and {#3}.}{}
\newenvironment{GCDLCM_B}[2]{\GCDorLCM{#1}\hspace{4cm}is maximized when \(x={#2}\).}{}
\title{}
\author{}
\begin{document}
\begin{GCDLCM_A}{1}{120}{84}
\end{GCDLCM_A}
\begin{GCDLCM_B}{0}{75}
\end{GCDLCM_B}
\end{document}