我正在尝试为矩阵中具有非空条目的单元格着色，但似乎\cellcolor不起作用。有什么解决办法吗？此外，第一列（矩阵外）的垂直点具有正常大小。我的代码如下：
\documentclass[10pt,xcolor={dvipsnames,table}]{beamer}
\mode<article> % only for the article version
{
\usepackage{fullpage}
\usepackage{hyperref}
}
\mode<presentation>
{
%\setbeamertemplate{background canvas}[vertical shading][bottom=red!10,top=blue!10]
\setbeamercovered{transparent}
\usefonttheme{serif}
\usecolortheme{crane}
}
\setbeamercovered{dynamic}
\setbeamertemplate{items}[circle]
\usepackage[table]{xcolor}
\usepackage{amsmath}
\usepackage{kbordermatrix}
\usepackage{tikz}
\usetikzlibrary{tikzmark}
\newcommand\x{\times}
\begin{document}
\begin{frame}
\begin{equation*}
\kbordermatrix{
& 2^{0} & 2^{1} & & 2^{2} & \ldots & 2^{m} & \ldots & n & \ldots & 2^{m+1} & \ldots \\
2^{0} & {\cellcolor{orange}1} & 0 & 0 & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
2^{1} & 0 & {\cellcolor{orange}1} & {\cellcolor{orange}1} & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
& 0 & {\cellcolor{orange}1} & {\cellcolor{orange}-1} & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
2^{2} & \vdots & \vdots & \vdots & \ddots & & \vdots & \vdots & & \vdots & \\
\vdots & \vdots & \vdots & \vdots & & \ddots & \vdots & \vdots & & \vdots & \\
2^{m} & 0 & 0 & 0 & \ldots & \ldots & {\cellcolor{orange}\x} & {\cellcolor{orange}\x} & {\cellcolor{orange}\ldots} & {\cellcolor{orange}\x} & \ldots & \ldots \\
\vdots & 0 & 0 & 0 & \ldots & \ldots & {\cellcolor{orange}\x} & {\cellcolor{orange}\x} & {\cellcolor{orange}\ldots} & {\cellcolor{orange}\x} & \ldots & \ldots \\
k & \vdots & \vdots & \vdots & & & {\cellcolor{orange}\vdots} & {\cellcolor{orange}\vdots} & {\cellcolor{orange}\ddots} & {\cellcolor{orange}\vdots} & \\
\vdots & 0 & 0 & 0 & \ldots & \ldots & {\cellcolor{orange}\x} & {\cellcolor{orange}\x} & {\cellcolor{orange}\ldots} & {\cellcolor{orange}\x} & \ldots & \ldots \\
2^{m+1} & \vdots & \vdots & \vdots & & & \vdots & \vdots & \vdots & \vdots & \ddots & \\
\vdots & \vdots & \vdots & \vdots & & & \vdots & \vdots & \vdots & \vdots & & \ddots
}
\end{equation*}
\end{frame}
\end{document}
答案1
如果您喜欢使用kbordermatrix，那么您将面临一些矩阵单元着色的问题。首先，它\cellcolor不起作用，因为它是为表格设计的；其次，可能的解决方案是使用colorbox，但结果并不令人满意：
\documentclass[10pt,xcolor={dvipsnames,table}]{beamer}
\setbeamercovered{dynamic}
\setbeamertemplate{items}[circle]
\usepackage[table]{xcolor}
\usepackage{kbordermatrix}
\usepackage{tikz}
\usetikzlibrary{tikzmark}
\usepackage{amsmath}
\newcommand\x{$\times$}
\newcommand\CB[1]{\colorbox{orange!30}{#1}}
\begin{document}
\begin{frame}
\[
\kbordermatrix{
& 2^{0} & 2^{1} & & 2^{2} & \ldots & 2^{m} & \ldots & n & \ldots & 2^{m+1} & \ldots \\
2^{0} & \CB{1} & 0 & 0 & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
2^{1} & 0 & \CB{1} & \CB{1} & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
& 0 & \CB{1} & \CB{-1} & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
2^{2} & \vdots & \vdots & \vdots & \ddots & & \vdots & \vdots & & \vdots & \\
\vdots & \vdots & \vdots & \vdots & & \ddots & \vdots & \vdots & & \vdots & \\
2^{m} & 0 & 0 & 0 & \ldots & \ldots & \CB{\x} &\CB{\x} & \CB{$\ldots$}
&\CB{\x} & \ldots & \ldots \\
\vdots & 0 & 0 & 0 & \ldots & \ldots & \CB{\x} &\CB{\x} & \CB{$\ldots$}
&\CB{\x} & \ldots & \ldots \\
k & \vdots & \vdots & \vdots & & & \CB{$\vdots$}
&\CB{$\vdots$}
&\CB{$\ddots$}
& \CB{$\vdots$} & \\
\vdots & 0 & 0 & 0 & \ldots & \ldots & \CB{\x} &\CB{\x} &\CB{$\ldots$}
&\CB{\x} & \ldots & \ldots \\
2^{m+1} & \vdots & \vdots & \vdots & & & \vdots & \vdots & \vdots & \vdots & \ddots & \\
\vdots & \vdots & \vdots & \vdots & & & \vdots & \vdots & \vdots & \vdots & & \ddots
}
\]
\end{frame}
\end{document}
编辑： 为了获得更好的结果，您应该遵循我在回答您上一个问题时给出的建议：
\documentclass[10pt,xcolor={dvipsnames,table}]{beamer}
\setbeamercovered{dynamic}
\setbeamertemplate{items}[circle]
\usepackage{tikz}
\usetikzlibrary{fit,
matrix,
positioning}
\tikzset{baseline = (current bounding box.center),
node distance= 1mm and 2mm,
M/.style = {matrix of math nodes,
nodes in empty cells,
nodes={minimum size=2em, inner sep=4pt, anchor=center},
column sep=2pt, row sep=2pt,
inner xsep=2pt, inner ysep=-2pt
},
CB/.style = {fill=orange!50},
lbl/.style = {text=gray, left=of #1}
}
\newcommand\svd{\raisebox{-2ex}{$\smash\vdots$}}
\newcommand\sdd{\raisebox{-2ex}{$\smash\ddots$}}
\newcommand\x{\times}
\begin{document}
\begin{frame}[fragile]
\[
\mathbf{D} = \tikz{
\matrix (n) [M, left delimiter={[},right delimiter={]}]
{
|[CB]| 1
& 0 & 0 & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
0 & |[CB]| 1 & |[CB]| 1 & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
0 & |[CB]| 1 & |[CB]| -1& \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
\svd & \sdd & \svd & |[CB]| \svd & |[CB]| \svd & |[CB]| \svd & |[CB]| \svd & \svd & \ldots & \ldots \\
0 & 0 & 0 & |[CB]| \ldots & |[CB]| \x & |[CB]| \x & |[CB]| \ldots & \x & \ldots & \ldots \\
0 & 0 & 0 & |[CB]| \ldots & |[CB]| \x & |[CB]| \x & |[CB]| \ldots & \x & \ldots & \ldots \\
\svd & \svd & & |[CB]| \svd & |[CB]| \svd & |[CB]| \sdd & |[CB]| \svd & & & \\
0 & 0 & 0 & \ldots & \x & \x & \ldots & \x & \ldots & \ldots \\
\svd & \svd & \svd & & \svd & \svd & \svd & \svd & \sdd & \\
\svd & \svd & \svd & & \svd & \svd & \svd & \svd & & \sdd \\
};
\node[lbl=n-1-1.west] {$2^{0}$};
\node[lbl=n-2-1] {$2^{1}$};
\node[lbl=n-3-1] {$2^{2}$};
\node[lbl=n-4-1] {$\svd$};
\node[lbl=n-5-1] {$2^{m}$};
\node[lbl=n-6-1] {$\svd$};
\node[lbl=n-7-1] {$k$};
\node[lbl=n-8-1] {$\svd$};
\node[lbl=n-9-1] {$2^{m+1}$};
\node[lbl=n-10-1] {$\svd$};
%
}% end of tikz
\]
\end{frame}
\end{document}
答案2
与{bNiceMatrix}nicematrix.
\documentclass[10pt,xcolor=dvipsnames]{beamer}
\setbeamercovered{dynamic}
\setbeamertemplate{items}[circle]
\usepackage{xcolor}
\usepackage{nicematrix}
\newcommand\x{\times}
\newcommand\CB[1]{\Block[fill=orange!30,draw=white,line-width=1pt]{}{#1}}
\begin{document}
\begin{frame}
\setcounter{MaxMatrixCols}{12}
\renewcommand{\arraystretch}{1.2}
\[
\begin{bNiceMatrix}[first-row,first-col,margin]
& 2^{0} & 2^{1} & & 2^{2} & \ldots & 2^{m} & \ldots & n & \ldots & 2^{m+1} & \ldots \\
2^{0} & \CB{1} & 0 & 0 & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
2^{1} & 0 & \CB{1} & \CB{1} & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
& 0 & \CB{1} & \CB{-1} & \ldots & \ldots & 0 & 0 & \ldots & 0 & \ldots & \ldots \\
2^{2} & \vdots & \vdots & \vdots & \ddots & & \vdots & \vdots & & \vdots & \\
\vdots & \vdots & \vdots & \vdots & & \ddots & \vdots & \vdots & & \vdots & \\
2^{m} & 0 & 0 & 0 & \ldots & \ldots & \CB{\x} &\CB{\x} & \CB{\ldots}
&\CB{\x} & \ldots & \ldots \\
\vdots & 0 & 0 & 0 & \ldots & \ldots & \CB{\x} &\CB{\x} & \CB{\ldots}
&\CB{\x} & \ldots & \ldots \\
k & \vdots & \vdots & \vdots & & & \CB{\vdots}
&\CB{\vdots}
&\CB{\ddots}
& \CB{\vdots} & \\
\vdots & 0 & 0 & 0 & \ldots & \ldots & \CB{\x} &\CB{\x} &\CB{\ldots}
&\CB{\x} & \ldots & \ldots \\
2^{m+1} & \vdots & \vdots & \vdots & & & \vdots & \vdots & \vdots & \vdots & \ddots & \\
\vdots & \vdots & \vdots & \vdots & & & \vdots & \vdots & \vdots & \vdots & & \ddots
\end{bNiceMatrix}
\]
\end{frame}
\end{document}
