对于问题 1 - 9，枚举编号和表达式之间的间距是正确的：
但对于第 10 题及后续问题，枚举号和表达式之间的最小距离太小，影响了可读性。我不希望学生在练习或考试中感到困惑。
这个问题有解决办法吗？
非常感谢您分享您的专业知识。
\documentclass[11pt]{exam}
\printanswers
% un-comment to print solutions.
\renewcommand{\solutiontitle}{}
\usepackage{amsmath}
\usepackage{cancel}
\usepackage{framed}
\usepackage{multicol}
\usepackage{tasks}
\usepackage[a4paper,margin=0.5in,include head]{geometry}
\usepackage{xcolor}
\usepackage{soul}
\pagestyle{head}
\header{Algebra II: Problem Set D}
{}
{Due 04/07/23}
\newcommand{\pagetop}{%
\noindent
\bigskip
\vspace{0.5mm}
}
\settasks{after-item-skip=1em,
after-skip=2cm,
label-width=1.5em, %<---------
item-indent=2em, %<---------
label=(\arabic*),
column-sep=1em %<----------
}
\begin{document}
%definition for bigskip = 1 line to replace all \bigskip
\def\bigskip{\vskip\bigskipamount}
\textbf{Simplify.}
\begin{tasks}
[style=enumerate](3)
% Prob #1
\task
$\sqrt{27}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{9}\sqrt{3}$
\bigskip
\hl{$=\mathbf{3\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #2
\task
$3\sqrt{48}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=3\sqrt{16}\sqrt{3}$
\bigskip
$(3)(4)\sqrt{3}$
\bigskip
\hl{$=\mathbf{12\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #3
\task
$5\sqrt{12}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=5\sqrt{4}\sqrt{3}$
\bigskip
$=(5)(2)\sqrt{3}$
\bigskip
\hl{$=\mathbf{10\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #4
\task
$\sqrt{x^{10}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}$
\bigskip
$=(x^1)(x^1)(x^1)(x^1)(x^1)$
\bigskip
\hl{$=\mathbf{x^5=x^{10\div2}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #5
\task
$\sqrt{a^{4}b^{12}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(a^{4\div2})(b^{12\div2})$
\bigskip
\hl{$=\mathbf{b^6x^2}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #6
\task
$2a^2\sqrt{a^8}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(2a^2)(a^{8\div2})$
\bigskip
$=(2a^2)(a^4)$
\bigskip
\hl{$=\mathbf{2a^{2+4}=2a^6}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #7
\task
$3ab^2\sqrt{4a^6b^{14}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(3ab^2)(2)(a^{6\div2)}(b^{14\div2})$
\bigskip
$=(3)(2)(a^1\cdot{a^3})(b^2\cdot b^7)$
\bigskip
\hl{$=\mathbf{6a^4b^9}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #8
\task
$5a\sqrt{18a^{20}b^{18}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(5a)(\sqrt{9})(\sqrt{2}(a^{20\div2})(b^{18\div2})$
\bigskip
$=(3)(2)(a^1\cdot{a^3})(b^2\cdot b^7)$
\bigskip
\hl{$=\mathbf{6a^4b^9}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #9
\task
$\sqrt{a^{11}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(\sqrt {a^{10}})(\sqrt{a^1})$
\bigskip
$=(a^{10\div2})(\sqrt{a^1})$
\bigskip
\hl{$=\mathbf{a^5\sqrt{a}}$}
\end{solutionorbox}
\bigskip
% Prob #10
\task
$2a\sqrt{a^{13}b^8}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=2a(\sqrt{a^{12}})(\sqrt{a^1})(\sqrt{b^8})$
\bigskip
$=2a(a^{12\div2})(b^{8\div2})(\sqrt{a})$
\bigskip
$=2a(a^6)(b^4)(\sqrt{a})$
\bigskip
\hl{$=\mathbf{2a^7b^4\sqrt{a}}$}
\end{solutionorbox}
% Prob #11
\task
$\sqrt{49x^7y^{15}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=7(\sqrt{x^6})(\sqrt{x^1})(\sqrt{y^{14}})(\sqrt{y^1})$
\bigskip
$=7(x^{6\div2})(y^{14\div2})(\sqrt{x}\sqrt{y})$
\bigskip
\hl{$=\mathbf{=7x^3y^7\sqrt{xy}}$}
\end{solutionorbox}
% Prob #12
\task
$\sqrt{24a^{17}b^{12}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(\sqrt{4})(\sqrt{6})(\sqrt{a^{17}})(\sqrt{b^{12}})$
\bigskip
$=(2\sqrt{6})(\sqrt {a^{16}})(\sqrt {a^1})(\sqrt {b^{12}})$
\bigskip
$=2\sqrt{6}(a^{16\div2})(\sqrt{a})(b^{12\div2})$
\bigskip
\hl{$\mathbf{=2\sqrt{6}a^8b^6\sqrt{a}}$}
\end{solutionorbox}
\bigskip
\task![]\textbf{Multiply and Simplify}% added <<<<<<<<<<
% Prob #13
\task
$\sqrt{10}\boldsymbol{\cdot} \sqrt{6} $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{60}$
\bigskip
$=(\sqrt{4})(\sqrt{15})$
\bigskip
\hl{$\mathbf{=2\sqrt{15}}$}
\end{solutionorbox}
\bigskip
% Prob #14
\task
$2(\sqrt{5}) (4\sqrt{10}) $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{60}$
\bigskip
$=(\sqrt{4})(\sqrt{15})$
\bigskip
\hl{$\mathbf{=2\sqrt{15}}$}
\end{solutionorbox}
\bigskip
% Prob #15
\task
$2(\sqrt{5}) (4\sqrt{10}) $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{7}\boldsymbol{\cdot}\sqrt{7}$
\bigskip
$=\sqrt{49}$
\bigskip
\hl{$\mathbf{=7}$}
\end{solutionorbox}
\bigskip
\end{tasks}
\vspace{0.25cm}
\end{document}
答案1
设置label-width为的宽度，(99)使其与使用的字体大小无关\settowidth。
对 使用相同的值 item-indent。
（请注意，有些solutionsorboxes需要更宽的宽度。您可以选择略小的边距以允许更宽的列，例如\usepackage[a4paper,margin=0.3in,include head]{geometry}）
\documentclass[11pt]{exam}
\printanswers
% un-comment to print solutions.
\renewcommand{\solutiontitle}{}
\usepackage{amsmath}
\usepackage{cancel}
\usepackage{framed}
\usepackage{multicol}
\usepackage{tasks}
\usepackage[a4paper,margin=0.3in,include head]{geometry} %changed <<<<<<<<<<<<<<<<<<<
\usepackage{xcolor}
\usepackage{soul}
\pagestyle{head}
\header{Algebra II: Problem Set D}
{}
{Due 04/07/23}
\newcommand{\pagetop}{%
\noindent
\bigskip
\vspace{0.5mm}
}
\newlength{\lwidth}% added
\settowidth{\lwidth}{(99)} % added
\settasks{after-item-skip=1em,
after-skip=2cm,
label-width=\lwidth, %<--------- changed
item-indent= 2.2em, %<--------- changed
label=(\arabic*),
column-sep=1em %<----------
}
\begin{document}
%definition for bigskip = 1 line to replace all \bigskip
\def\bigskip{\vskip\bigskipamount}
\textbf{Simplify.}
\begin{tasks}
[style=enumerate](3)
% Prob #1
\task
$\sqrt{27}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{9}\sqrt{3}$
\bigskip
\hl{$=\mathbf{3\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #2
\task
$3\sqrt{48}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=3\sqrt{16}\sqrt{3}$
\bigskip
$(3)(4)\sqrt{3}$
\bigskip
\hl{$=\mathbf{12\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #3
\task
$5\sqrt{12}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=5\sqrt{4}\sqrt{3}$
\bigskip
$=(5)(2)\sqrt{3}$
\bigskip
\hl{$=\mathbf{10\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #4
\task
$\sqrt{x^{10}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}$
\bigskip
$=(x^1)(x^1)(x^1)(x^1)(x^1)$
\bigskip
\hl{$=\mathbf{x^5=x^{10\div2}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #5
\task
$\sqrt{a^{4}b^{12}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(a^{4\div2})(b^{12\div2})$
\bigskip
\hl{$=\mathbf{b^6x^2}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #6
\task
$2a^2\sqrt{a^8}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(2a^2)(a^{8\div2})$
\bigskip
$=(2a^2)(a^4)$
\bigskip
\hl{$=\mathbf{2a^{2+4}=2a^6}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #7
\task
$3ab^2\sqrt{4a^6b^{14}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(3ab^2)(2)(a^{6\div2)}(b^{14\div2})$
\bigskip
$=(3)(2)(a^1\cdot{a^3})(b^2\cdot b^7)$
\bigskip
\hl{$=\mathbf{6a^4b^9}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #8
\task
$5a\sqrt{18a^{20}b^{18}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(5a)(\sqrt{9})(\sqrt{2}(a^{20\div2})(b^{18\div2})$
\bigskip
$=(3)(2)(a^1\cdot{a^3})(b^2\cdot b^7)$
\bigskip
\hl{$=\mathbf{6a^4b^9}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #9
\task
$\sqrt{a^{11}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(\sqrt {a^{10}})(\sqrt{a^1})$
\bigskip
$=(a^{10\div2})(\sqrt{a^1})$
\bigskip
\hl{$=\mathbf{a^5\sqrt{a}}$}
\end{solutionorbox}
\bigskip
% Prob #10
\task
$2a\sqrt{a^{13}b^8}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=2a(\sqrt{a^{12}})(\sqrt{a^1})(\sqrt{b^8})$
\bigskip
$=2a(a^{12\div2})(b^{8\div2})(\sqrt{a})$
\bigskip
$=2a(a^6)(b^4)(\sqrt{a})$
\bigskip
\hl{$=\mathbf{2a^7b^4\sqrt{a}}$}
\end{solutionorbox}
% Prob #11
\task
$\sqrt{49x^7y^{15}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=7(\sqrt{x^6})(\sqrt{x^1})(\sqrt{y^{14}})(\sqrt{y^1})$
\bigskip
$=7(x^{6\div2})(y^{14\div2})(\sqrt{x}\sqrt{y})$
\bigskip
\hl{$=\mathbf{=7x^3y^7\sqrt{xy}}$}
\end{solutionorbox}
% Prob #12
\task
$\sqrt{24a^{17}b^{12}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(\sqrt{4})(\sqrt{6})(\sqrt{a^{17}})(\sqrt{b^{12}})$
\bigskip
$=(2\sqrt{6})(\sqrt {a^{16}})(\sqrt {a^1})(\sqrt {b^{12}})$
\bigskip
$=2\sqrt{6}(a^{16\div2})(\sqrt{a})(b^{12\div2})$
\bigskip
\hl{$\mathbf{=2\sqrt{6}a^8b^6\sqrt{a}}$}
\end{solutionorbox}
\bigskip
\task![]\textbf{Multiply and Simplify}% added <<<<<<<<<<
% Prob #13
\task
$\sqrt{10}\boldsymbol{\cdot} \sqrt{6} $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{60}$
\bigskip
$=(\sqrt{4})(\sqrt{15})$
\bigskip
\hl{$\mathbf{=2\sqrt{15}}$}
\end{solutionorbox}
\bigskip
% Prob #14
\task
$2(\sqrt{5}) (4\sqrt{10}) $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{60}$
\bigskip
$=(\sqrt{4})(\sqrt{15})$
\bigskip
\hl{$\mathbf{=2\sqrt{15}}$}
\end{solutionorbox}
\bigskip
% Prob #15
\task
$2(\sqrt{5}) (4\sqrt{10}) $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{7}\boldsymbol{\cdot}\sqrt{7}$
\bigskip
$=\sqrt{49}$
\bigskip
\hl{$\mathbf{=7}$}
\end{solutionorbox}
\bigskip
\end{tasks}
\vspace{0.25cm}
\end{document}
更新后续问题：将枚举与解决方案框的左侧对齐。
\documentclass[11pt]{exam}
\printanswers
% un-comment to print solutions.
\renewcommand{\solutiontitle}{}
\usepackage{amsmath}
\usepackage{cancel}
\usepackage{framed}
\usepackage{multicol}
\usepackage{tasks}
\usepackage[a4paper,margin=0.5in,include head]{geometry}
\usepackage{xcolor}
\usepackage{soul}
\pagestyle{head}
\header{Algebra II: Problem Set D}
{}
{Due 04/07/23}
\newcommand{\pagetop}{%
\noindent
\bigskip
\vspace{0.5mm}
}
%**************************************************** only this code was added/ modified
\newlength{\lwidth}% added <<<<<
\settowidth{\lwidth}{(99)\enspace} % added
\settasks{after-item-skip=1em,
after-skip=2cm,
label-width=\lwidth, % changed <<<<<<<<<
item-indent=0pt, % changed <<<<<<<<<<
label=(\bfseries \arabic*), % changed <<<<<<<<<<
label-offset = -\lwidth,% added <<<<<
item-format = \hspace{\lwidth},% added <<<<<
column-sep=2em, % changed <<<<<<<<<
}
%****************************************************
\begin{document}
%definition for bigskip = 1 line to replace all \bigskip
\def\bigskip{\vskip\bigskipamount}
\textbf{Simplify.}
\begin{tasks}
[style=enumerate](3)
% Prob #1
\task
$\sqrt{27}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{9}\sqrt{3}$
\bigskip
\hl{$=\mathbf{3\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #2
\task
$3\sqrt{48}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=3\sqrt{16}\sqrt{3}$
\bigskip
$(3)(4)\sqrt{3}$
\bigskip
\hl{$=\mathbf{12\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #3
\task
$5\sqrt{12}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=5\sqrt{4}\sqrt{3}$
\bigskip
$=(5)(2)\sqrt{3}$
\bigskip
\hl{$=\mathbf{10\sqrt{3}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #4
\task
$\sqrt{x^{10}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}$
\bigskip
$=(x^1)(x^1)(x^1)(x^1)(x^1)$
\bigskip
\hl{$=\mathbf{x^5=x^{10\div2}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #5
\task
$\sqrt{a^{4}b^{12}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(a^{4\div2})(b^{12\div2})$
\bigskip
\hl{$=\mathbf{b^6x^2}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #6
\task
$2a^2\sqrt{a^8}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(2a^2)(a^{8\div2})$
\bigskip
$=(2a^2)(a^4)$
\bigskip
\hl{$=\mathbf{2a^{2+4}=2a^6}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #7
\task
$3ab^2\sqrt{4a^6b^{14}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(3ab^2)(2)(a^{6\div2)}(b^{14\div2})$
\bigskip
$=(3)(2)(a^1\cdot{a^3})(b^2\cdot b^7)$
\bigskip
\hl{$=\mathbf{6a^4b^9}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #8
\task
$5a\sqrt{18a^{20}b^{18}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(5a)(\sqrt{9})(\sqrt{2}(a^{20\div2})(b^{18\div2})$
\bigskip
$=(3)(2)(a^1\cdot{a^3})(b^2\cdot b^7)$
\bigskip
\hl{$=\mathbf{6a^4b^9}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #9
\task
$\sqrt{a^{11}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(\sqrt {a^{10}})(\sqrt{a^1})$
\bigskip
$=(a^{10\div2})(\sqrt{a^1})$
\bigskip
\hl{$=\mathbf{a^5\sqrt{a}}$}
\end{solutionorbox}
\bigskip
% Prob #10
\task
$2a\sqrt{a^{13}b^8}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=2a(\sqrt{a^{12}})(\sqrt{a^1})(\sqrt{b^8})$
\bigskip
$=2a(a^{12\div2})(b^{8\div2})(\sqrt{a})$
\bigskip
$=2a(a^6)(b^4)(\sqrt{a})$
\bigskip
\hl{$=\mathbf{2a^7b^4\sqrt{a}}$}
\end{solutionorbox}
% Prob #11
\task
$\sqrt{49x^7y^{15}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=7(\sqrt{x^6})(\sqrt{x^1})(\sqrt{y^{14}})(\sqrt{y^1})$
\bigskip
$=7(x^{6\div2})(y^{14\div2})(\sqrt{x}\sqrt{y})$
\bigskip
\hl{$=\mathbf{=7x^3y^7\sqrt{xy}}$}
\end{solutionorbox}
% Prob #12
\task
$\sqrt{24a^{17}b^{12}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=(\sqrt{4})(\sqrt{6})(\sqrt{a^{17}})(\sqrt{b^{12}})$
\bigskip
$=(2\sqrt{6})(\sqrt {a^{16}})(\sqrt {a^1})(\sqrt {b^{12}})$
\bigskip
$=2\sqrt{6}(a^{16\div2})(\sqrt{a})(b^{12\div2})$
\bigskip
\hl{$\mathbf{=2\sqrt{6}a^8b^6\sqrt{a}}$}
\end{solutionorbox}
\bigskip
\task![]\textbf{Multiply and Simplify}% added <<<<<<<<<<
% Prob #13
\task
$\sqrt{10}\boldsymbol{\cdot} \sqrt{6} $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{60}$
\bigskip
$=(\sqrt{4})(\sqrt{15})$
\bigskip
\hl{$\mathbf{=2\sqrt{15}}$}
\end{solutionorbox}
\bigskip
% Prob #14
\task
$2(\sqrt{5}) (4\sqrt{10}) $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{60}$
\bigskip
$=(\sqrt{4})(\sqrt{15})$
\bigskip
\hl{$\mathbf{=2\sqrt{15}}$}
\end{solutionorbox}
\bigskip
% Prob #15
\task
$2(\sqrt{5}) (4\sqrt{10}) $
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\sqrt{10\boldsymbol{\cdot}6}$
\bigskip
$=\sqrt{7}\boldsymbol{\cdot}\sqrt{7}$
\bigskip
$=\sqrt{49}$
\bigskip
\hl{$\mathbf{=7}$}
\end{solutionorbox}
\bigskip
\end{tasks}
\vspace{0.25cm}
\end{document}
你可能想要使用
\task![]\hspace{-\lwidth}\textbf{Simplify}
和
\task![]\hspace{-\lwidth}\textbf{Multiply and Simplify}
将标题左对齐。