请告诉我为什么 \bm 和 amsmath 中的 \dfrac 不能很好地配合。
此代码\hl{$=\bm{\frac{7\sqrt[3]{2}}{2}}$}
产生:
但\hl{$=\bm{\dfrac{7\sqrt[3]{2}}{2}}$}
会导致编译器崩溃。
我之所以使用它是\dfrac
因为在我看来得到的分数更容易阅读。
那么为什么\bm
不兼容\dfrac
?
非常感谢您的帮助!
母语:
\documentclass[11pt]{exam}
\printanswers
% un-comment to print solutions.
\renewcommand{\solutiontitle}{}
\usepackage{amsmath}
\usepackage{bm}
\usepackage{framed}
\usepackage{multicol}
\usepackage{tasks}
\usepackage[a4paper,margin=0.5in,include head]{geometry}
\usepackage{soul}
\usepackage{xcolor}
\thispagestyle{myheadings}
\markright{\normalfont\textbf{Algebra II: Unit 12 Radical Expressions Other Roots 12 AB 2}\hfill 04/17/23}
\newcommand{\pagetop}{%
\noindent
\bigskip
\vspace{0.5mm}
}
%%\settasks{after-item-skip=1em,
%% after-skip=2cm,
%% label-width=1.5em, %<---------
%% item-indent=2em, %<---------
%% label=(\arabic*),
%% column-sep=1em %<----------
%%}
%**************************************************** only this code was added/ modified
\newlength{\lwidth}% added <<<<<
\settowidth{\lwidth}{(99)\enspace} % added
\settasks{after-item-skip=1em,
after-skip=2cm,
label-width=\lwidth, % changed <<<<<<<<<
item-indent=0pt, % changed <<<<<<<<<<
label-format = \bfseries, % numbers in bold added <<<<<<<<<<
label=(\arabic*), %
label-offset = -\lwidth,% added <<<<<
item-format = \hspace{\lwidth},% added <<<<<
column-sep=2em, % changed <<<<<<<<<
}
%****************************************************
\begin{document}
%definition for bigskip = 1 line to replace all \bigskip
\def\bigskip{\vskip\bigskipamount}
\textbf{Simplify.}
\begin{tasks}
[style=enumerate](3)
% Prob #1
\task
$\sqrt[3]{8}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$8$ is a perfect cube.
\bigskip
\hl{$\bm{\sqrt[3]{8}=2}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #2
\task
$\sqrt[3]{250}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
Find perfect cube factor of $250$
\bigskip
$=(\sqrt[3]{125})(\sqrt[3]{2})$
\bigskip
\hl{$=\bm{5\sqrt[3]{2}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #3
\task
$\sqrt[4]{64}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
Prime factorization of $64=2^6$
\bigskip
$\sqrt[4]{2^6}=(\sqrt[4]{2^4})(\sqrt[4]{2^4})$
\bigskip
$=2\sqrt[4]{2^2}$
\bigskip
$=2\bm{\cdot}2^{2\bm{\div}4}$
\bigskip
\hl{$=\bm {2{\sqrt{2}}}$}
\end{solutionorbox}
\vspace{0.25cm}
% Prob #12
\task
$\dfrac{7}{\sqrt[3]{2}}$
\vspace{3mm}
\begin{solutionorbox}[3cm]
$=\dfrac{7}{\sqrt[3]{2}}\bm{\cdot}\dfrac{\sqrt[3]{2^2}}{\sqrt[3]{2^2}}$
\bigskip
$=\dfrac{7\sqrt[3]{2^2}}{(\sqrt[3]{2})(\sqrt[3]{2^2})}$
\bigskip
$=\dfrac{7\sqrt[3]{2^2}}{\sqrt[3]{2^3}}$
\bigskip
\hl{$=\bm{\frac{7\sqrt[3]{2}}{2}}$}
\end{solutionorbox}
\vspace{0.25cm}
\newpage
\end{tasks}
\end{document}
答案1
不要使用\dfrac
; 而是改变
\hl{$=\bm{\frac{7\sqrt[3]{2}}{2}}$}
到
\hl{$\displaystyle=\bm{\frac{7\sqrt[3]{2}}{2}}$}
但是,高亮带无法覆盖整个表情。到目前为止,更好的方法是
\colorbox{yellow}{$\displaystyle=\bm{\frac{7\sqrt[3]{2}}{2}}$}
\documentclass[11pt]{exam}
\usepackage{amsmath,bm}
\usepackage{soul} % for \hl macro
\usepackage{xcolor} % for \colorbox macro
\begin{document}
\hl{$=\bm{\frac{7\sqrt[3]{2}}{2}}$}
\qquad
\hl{$\displaystyle=\bm{\frac{7\sqrt[3]{2}}{2}}$}
\qquad
\colorbox{yellow}{$\displaystyle=\bm{\frac{7\sqrt[3]{2}}{2}}$}
\end{document}