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如何在 IEEE Access Latex 双列模板中容纳长数组？

tag-icon • tag-icon overleaf two-column arrays ieeeaccess
如何在 IEEE Access Latex 双列模板中容纳长数组？

我目前正在使用 IEEE Access Latex 格式进行编写。我所做的工作涉及长数组，而我在单列中处理这些数组时遇到了困难。数组往往会与下一列中的文本重叠。

（数组与文本重叠。（https://i.stack.imgur.com/6yyFR.jpg）

以下是数组：

 $H_\mathbb{\mathbb{P}}
=${\scriptsize$\left\{\begin{matrix}{c}H_{\widehat{p}_1}=\{ \langle
\varrho_1,([0.3,0.5],[0.1,0.5]),(0.4,0.6)\rangle, \langle
\varrho_2,([0.3,0.4],[0.1,0.5]),(0.4,0.5)\rangle, \langle \varrho_3,([0.2,0.6],[0.1,0.4]),(0.3,0.6))\rangle \},\\
H_{\widehat{p}_2}=\{ \langle
\varrho_1,([0.1,0.4],[0.4,0.6]),(0.2,0.7)\rangle, \langle
\varrho_2,([0.2,0.4],[0.5,0.6]),(0.1,0.4)\rangle, \langle \varrho_3,([0.3,0.8],[0.1,0.2]),(0.6,0.1)\rangle \},\\
H_{\widehat{p}_3}=\{ \langle
\varrho_1,([0.2,0.6],[0.1,0.3]),(0.2,0.6)\rangle, \langle
\varrho_2,([0.2,0.4],[0.1,0.4]),(0.3,0.5)\rangle, \langle \varrho_3,([0.1,0.2],[0.3,0.8]),(0.3,0.5)\rangle\},\\
H_{\widehat{p}_4}=\{ \langle
\varrho_1,([0.1,0.4],[0.3,0.6]),(0.1,0.8)\rangle,\langle
\varrho_2,([0.1,0.5],[0.1,0.3]),(0.3,0.5)\rangle, \langle \varrho_3,([0.2,0.3],[0.2,0.7]),(0.2,0.4)\rangle \}\\
                   \end{matrix}
                 \right \}$


\begin{center}
$I_\mathbb{\mathbb{P}}
=${\scriptsize$\left\{\begin{array}{c}H_{\widehat{p}_1}=\{ \langle
\varrho_1,([0.2,0.7],[0.1,0.2]),(0.3,0.5)\rangle, \langle
\varrho_2,([0.3,0.6],[0.2,0.4]),(0.4,0.6)\rangle, \langle \varrho_3,([0.4,0.5],[0.2,0.4]),(0.6,0.3))\rangle \},\\
H_{\widehat{p}_2}=\{ \langle
\varrho_1,([0.1,0.5],[0.3,0.5]),(0.5,0.4)\rangle, \langle
\varrho_2,([0.2,0.4],[0.5,0.6]),(0.1,0.9)\rangle, \langle \varrho_3,([0.2,0.6],[0.1,0.3]),(0.5,0.4)\rangle \},\\
H_{\widehat{p}_3}=\{ \langle
\varrho_1,([0.6,0.8],[0.1,0.2]),(0.4,0.5)\rangle, \langle
\varrho_2,([0.1,0.6],[0.1,0.3]),(0.2,0.8)\rangle, \langle \varrho_3,([0.1,0.3],[0.2,0.7]),(0.2,0.4)\rangle\},\\
H_{\widehat{p}_4}=\{ \langle
\varrho_1,([0.3,0.4],[0.5,0.6]),(0.6,0.3)\rangle,\langle
\varrho_2,([0.7,0.8],[0.1,0.2]),(0.7,0.2)\rangle, \langle \varrho_3,([0.6,0.7],[0.2,0.3]),(0.1,0.5)\rangle \}\\
                   \end{array}
                 \right \}$}
\end{center}
\begin{center}
$J_\mathbb{\mathbb{P}}
=${$\left\{\begin{array}{c}H_{\widehat{p}_1}=\{ \langle
\varrho_1,([0.2,0.5],[0.1,0.4]),(0.6,0.2)\rangle, \langle
\varrho_2,([0.1,0.3],[0.2,0.7]),(0.7,0.1)\rangle, \langle \varrho_3,([0.5,0.8],[0.1,0.2]),(0.9,0.1))\rangle \},\\
H_{\widehat{p}_2}=\{ \langle
\varrho_1,([0.4,0.5],[0.1,0.3]),(0.6,0.3)\rangle, \langle
\varrho_2,([0.3,0.6],[0.2,0.4]),(0.2,0.7)\rangle, \langle \varrho_3,([0.4,0.6],[0.2,0.3]),(0.2,0.8)\rangle \},\\
H_{\widehat{p}_3}=\{ \langle
\varrho_1,([0.3,0.8],[0.1,0.2]),(0.3,0.6)\rangle, \langle
\varrho_2,([0.1,0.5],[0.3,0.5]),(0.3,0.4)\rangle, \langle \varrho_3,([0.2,0.4],[0.1,0.3]),(0.4,0.3)\rangle\},\\
H_{\widehat{p}_4}=\{ \langle
\varrho_1,([0.3,0.6],[0.1,0.3]),(0.1,0.5)\rangle,\langle
\varrho_2,([0.4,0.5],[0.2,0.4]),(0.7,0.2)\rangle, \langle \varrho_3,([0.7,0.8],[0.1,0.2]),(0.8,0.1)\rangle \}\\
                   \end{array}
                 \right \}$}
\end{center}

\noindent Now, a reference set is used for comparison of the alternatives so the closest to the ideal alternative is selected. Assume the properties of an ideal storage facility for cement are recorded in the form of an n-tuple to see the 
highest level of n-tuple compliance with $H_\mathbb{\mathbb{P}}$, $I_\mathbb{\mathbb{P}}$ and $J_\mathbb{\mathbb{P}}$.
For this purpose, a list is compiled with different storage options they have currently available out of which their aim is to the select the closest to the ideal option. Most of the data for considering the similarity between the presented options is available in the form of human intuition allowing room for uncertainty which is best dealt using fuzzy structures. The list in the form of CIFHSS is shown below:

\begin{center}

   $$ R_\mathbb{\mathbb{P}}
={\left\{\begin{array}{c}H_{\widehat{p}_1}=\{ \langle
\varrho_1,([0.1,0.3],[0.2,0.5]),(0.6,0.3)\rangle, \langle
\varrho_2,([0.5,0.6],[0.3,0.4]),(0.2,0.7)\rangle, \langle \varrho_3,([0.3,0.8],[0.1,0.2]),(0.2,0.7))\rangle \},\\
H_{\widehat{p}_2}=\{ \langle
\varrho_1,([0.3,0.6],[0.2,0.3]),(0.8,0.1)\rangle, \langle
\varrho_2,([0.1,0.4],[0.2,0.6]),(0.3,0.5)\rangle, \langle M\varrho_3,([0.4,0.5],[0.3,0.4]),(0.3,0.6)\rangle \},\\
H_{\widehat{p}_3}=\{ \langle
\varrho_1,([0.1,0.6],[0.2,0.3]),(0.3,0.5)\rangle, \langle
\varrho_2,([0.2,0.5],[0.3,0.5]),(0.1,0.4)\rangle, \langle \varrho_3,([0.1,0.8],[0.1,0.2]),(0.2,0.7)\rangle\},\\
H_{\widehat{p}_4}=\{ \langle
\varrho_1,([0.4,0.5],[0.2,0.4]),(0.1,0.8)\rangle,\langle
\varrho_2,([0.6,0.7],[0.1,0.3]),(0.7,0.1)\rangle, \langle \varrho_3,([0.5,0.8],[0.1,0.2]),(0.4,0.6)\rangle \}\\
                   \end{array}
                 \right \}}$$
                 \end{center}

现在，我还附加了一个链接，可引导任何人访问 IEEE Access 模板 (https://www.overleaf.com/latex/templates/ieee-access-latex-template/cdxrhtbjgszv）。

请帮助我调整这些数组，使其位于页面的中心或单列中。

谢谢

我曾尝试改变数组的大小，也尝试过破坏数组，但这两件事都没有成功。

答案1

（评论太长，因此作为答案发布）

恐怕您的数组实在太大，无法放在一列中。我已经清理了数组的代码；它的宽度是 值的两倍多\columnwidth。即使切换到\tiny—— 字体大小线性减少 50% —— 数组的宽度仍然远远超过了\columnwidth。

我认为你唯一的选择是想出一种完全不同的方法来显示数组的内容。例如，你能否将每行的组件分解成更小的部分，然后单独显示这些组件，而不是显示一个又长又复杂的行？

在此处输入图片描述

\documentclass[demo]{IEEEaccess} % remove 'demo' option in real doc.
\usepackage{amsmath,amssymb}
\usepackage{graphicx}
\usepackage{lipsum}

\begin{document}

\lipsum[1][1-8] % a few lines of filler text
\[
H_{\mathbb{P}} =
\begin{Bmatrix}
H_{\hat{p}_1}=
\langle \varrho_1,([0.3,0.5],[0.1,0.5]),(0.4,0.6)\rangle, 
\langle \varrho_2,([0.3,0.4],[0.1,0.5]),(0.4,0.5)\rangle, 
\langle \varrho_3,([0.2,0.6],[0.1,0.4]),(0.3,0.6)\rangle,\\
H_{\hat{p}_2}=
\langle \varrho_1,([0.1,0.4],[0.4,0.6]),(0.2,0.7)\rangle, 
\langle \varrho_2,([0.2,0.4],[0.5,0.6]),(0.1,0.4)\rangle, 
\langle \varrho_3,([0.3,0.8],[0.1,0.2]),(0.6,0.1)\rangle,\\
H_{\hat{p}_3}=
\langle \varrho_1,([0.2,0.6],[0.1,0.3]),(0.2,0.6)\rangle, 
\langle \varrho_2,([0.2,0.4],[0.1,0.4]),(0.3,0.5)\rangle, 
\langle \varrho_3,([0.1,0.2],[0.3,0.8]),(0.3,0.5)\rangle,\\
H_{\hat{p}_4}=
\langle \varrho_1,([0.1,0.4],[0.3,0.6]),(0.1,0.8)\rangle,
\langle \varrho_2,([0.1,0.5],[0.1,0.3]),(0.3,0.5)\rangle, 
\langle \varrho_3,([0.2,0.3],[0.2,0.7]),(0.2,0.4)\rangle \\
\end{Bmatrix}
\]
\lipsum[1][9-12] % more filler text

\bigskip
\tiny
\lipsum[1][1-8] % a few lines of filler text
\[
H_{\mathbb{P}} =
\begin{Bmatrix}
H_{\hat{p}_1}=
\langle \varrho_1,([0.3,0.5],[0.1,0.5]),(0.4,0.6)\rangle, 
\langle \varrho_2,([0.3,0.4],[0.1,0.5]),(0.4,0.5)\rangle, 
\langle \varrho_3,([0.2,0.6],[0.1,0.4]),(0.3,0.6)\rangle,\\
H_{\hat{p}_2}=
\langle \varrho_1,([0.1,0.4],[0.4,0.6]),(0.2,0.7)\rangle, 
\langle \varrho_2,([0.2,0.4],[0.5,0.6]),(0.1,0.4)\rangle, 
\langle \varrho_3,([0.3,0.8],[0.1,0.2]),(0.6,0.1)\rangle,\\
H_{\hat{p}_3}=
\langle \varrho_1,([0.2,0.6],[0.1,0.3]),(0.2,0.6)\rangle, 
\langle \varrho_2,([0.2,0.4],[0.1,0.4]),(0.3,0.5)\rangle, 
\langle \varrho_3,([0.1,0.2],[0.3,0.8]),(0.3,0.5)\rangle,\\
H_{\hat{p}_4}=
\langle \varrho_1,([0.1,0.4],[0.3,0.6]),(0.1,0.8)\rangle,
\langle \varrho_2,([0.1,0.5],[0.1,0.3]),(0.3,0.5)\rangle, 
\langle \varrho_3,([0.2,0.3],[0.2,0.7]),(0.2,0.4)\rangle \\
\end{Bmatrix}
\]
\lipsum[1][9-12] % more filler text

\EOD
\end{document}

附录解决 OP 的后续评论。我认为你最好将四个大表达式以table横向模式单独放在一页上。然后，从文本中引用对象。

在此处输入图片描述

\documentclass[demo]{IEEEaccess} % remove 'demo' option in real doc.
\usepackage{amsmath,amssymb}
\usepackage{newtxtext,newtxmath}
\usepackage{graphicx}
\usepackage{pdflscape}
\usepackage{afterpage}
\usepackage{lipsum} % for filler text

\begin{document}

\lipsum[1-6] % filler text

\afterpage{ % defer execution until start of next page
\begin{landscape}
\begin{table}
\caption{Some tuples}

\begin{align*}
H_{\mathbb{P}} &=
\begin{Bmatrix}
\begin{aligned}
c H_{\hat{p}_1} &=
\langle \varrho_1,([0.3,0.5],[0.1,0.5]),(0.4,0.6)\rangle, 
\langle \varrho_2,([0.3,0.4],[0.1,0.5]),(0.4,0.5)\rangle, 
\langle \varrho_3,([0.2,0.6],[0.1,0.4]),(0.3,0.6)\rangle,\\
H_{\hat{p}_2} &=
\langle \varrho_1,([0.1,0.4],[0.4,0.6]),(0.2,0.7)\rangle, 
\langle \varrho_2,([0.2,0.4],[0.5,0.6]),(0.1,0.4)\rangle, 
\langle \varrho_3,([0.3,0.8],[0.1,0.2]),(0.6,0.1)\rangle,\\
H_{\hat{p}_3} &=
\langle \varrho_1,([0.2,0.6],[0.1,0.3]),(0.2,0.6)\rangle, 
\langle \varrho_2,([0.2,0.4],[0.1,0.4]),(0.3,0.5)\rangle, 
\langle \varrho_3,([0.1,0.2],[0.3,0.8]),(0.3,0.5)\rangle,\\
H_{\hat{p}_4} &=
\langle \varrho_1,([0.1,0.4],[0.3,0.6]),(0.1,0.8)\rangle,
\langle \varrho_2,([0.1,0.5],[0.1,0.3]),(0.3,0.5)\rangle, 
\langle \varrho_3,([0.2,0.3],[0.2,0.7]),(0.2,0.4)\rangle \ 
\end{aligned}
\end{Bmatrix} \\[3\jot] % a bit more vertical separation
I_{\mathbb{P}} &= 
\begin{Bmatrix}
\begin{aligned}
H_{\hat{p}_1} &= \dots \\
H_{\hat{p}_2} &= \dots \\
H_{\hat{p}_3} &= \dots \\
H_{\hat{p}_4} &= \dots \ 
\end{aligned}
\end{Bmatrix} \\[3\jot]
J_{\mathbb{P}} &= 
\begin{Bmatrix}
\begin{aligned}
H_{\hat{p}_1} &= \dots \\
H_{\hat{p}_2} &= \dots \\
H_{\hat{p}_3} &= \dots \\
H_{\hat{p}_4} &= \dots \ 
\end{aligned}
\end{Bmatrix} \\[3\jot]
R_{\mathbb{P}} &= 
\begin{Bmatrix}
\begin{aligned}
H_{\hat{p}_1} &= \dots \\
H_{\hat{p}_2} &= \dots \\
H_{\hat{p}_3} &= \dots \\
H_{\hat{p}_4} &= \dots \ 
\end{aligned}
\end{Bmatrix} 
\end{align*}

\end{table}
\end{landscape}
\clearpage
}

\lipsum[7-19] % more filler text

\EOD
\end{document}

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