我有这个公式，它在编译时超出了页面范围。它太大了，\tiny无法剪切。我需要使用调整大小框，但公式处于对齐环境中。公式需要标记为块，可以吗？
ps：等式不能改变
有什么建议么？
\documentclass[a4paper,12pt]{book}
\usepackage{graphicx}
\usepackage[inner=3.8cm, outer=1.3cm, top=2.5cm, bottom=1.2cm]{geometry}
%\usepackage[utf8]{inputenc} % that's the default nowadays
\usepackage[T1]{fontenc} % <-- new
\usepackage{amssymb,mathtools}
\allowdisplaybreaks
\begin{document}
\begin{align*}
c_{11}&=1\\
c_{12}&=-\frac{160 {x_{n+1}^9}+2520 h {x_{n+1}^8}+16560 {h^2} {x_{n+1}^7}+58800 {h^3} {x_{n+1}^6}+121842 {h^4} {x_{n+1}^5}+147735 {h^5} {x_{n+1}^4}+98010 {h^6} {x_{n+1sing}^3}+28350 {h^7} {x_{n+1}^2}-473977 {h^9}}{2041200 {h^8}}\\
c_{13}&=\frac{320 {x_{n+1}^9}+4680 h {x_{n+1}^8}+27360 {h^2} {x_{n+1}^7}+78960 {h^3} {x_{n+1}^6}+102564 {h^4} {x_{n+1}^5}-9135 {h^5} {x_{n+1}^4}-197940 {h^6} {x_{n+1}^3}-237330 {h^7} {x_{n+1}^2}-113400 {h^8} {x_{n+1}}+343921 {h^9}}{113400 {h^8}}\\
c_{14}&=-\frac{1120 {x_{n+1}^9}+15750 h {x_{n+1}^8}+86760 {h^2} {x_{n+1}^7}+225750 {h^3} {x_{n+1}^6}+223524 {h^4} {x_{n+1}^5}-171675 {h^5} {x_{n+1}^4}-578340 {h^6} {x_{n+1}^3}-396900 {h^7} {x_{n+1}^2}+594011 {h^9}}{85050 {h^8}}\\
c_{15}&=\frac{560 {x_{n+1}^{9}}+7560 h {x_{n+1}^{8}}+39240 {{h}^{2}} {x_{n+1}^{7}}+92400 {{h}^{3}} {x_{n+1}^{6}}+68607 {{h}^{4}} {x_{n+1}^{5}}-101745 {{h}^{5}} {x_{ n+1}^{4}}-210735 {{h}^{6}} {x_{n+1}^{3}}-99225 {{h}^{7}} {x_{n+1}^{2}}+203338 {{h}^{9}}}{18900 {{h}^{8}}} \\
c_{16}&=-\frac{1120 {x_{n+1}^{9}}+14490 h {x_{n+1}^{8}}+70920 {{h}^{2}} {x_{n+1}^{7}}+152250 {{h}^{3}} {x_{n+1}^{6}}+84924 {{h}^{4}} {x_{n+1}^{5}}-191205 {{h}^{5}} {x_{n+1}^{4}}-310380 {{h}^{6}} {x_{n+1}^{3}}-132300 {{h}^{7}} {x_{n+1}^{2}}+310181 {{h}^{9}}}{28350 {{h}^{8}}}\\
c_{17}&=\frac{2240 {x_{n+1}^{9}}+27720 h {x_{n+1}^{8}}+128160 {{h}^{2}} {x_{n+1}^{7}}+253680 {{h}^{3}} {x_{n+1}^{6}}+109116 {{h}^{4}} {x_{n+1}^{5}}-336735 {{h}^{5}} {x_{n+1}^{4}}-487620 {{h}^{6}} {x_{n+1}^{3}}-198450 {{h}^{7}} {x_{n+1}^{2}}+501889 {{h}^{9}}}{68040 {{h}^{8}}}\\
c_{18}&=-\frac{160 {x_{n+1}^{9}}+1890 h {x_{n+1}^{8}}+8280 {{h}^{2}} {x_{n+1}^{7}}+15330 {{h}^{3}} {x_{n+1} ^{6}}+5292 {{h}^{4}} {x_{n+1}^{5}}-21105 {{h}^{5}} {x_{n+1}^{4}}-28620 {{h}^{6}} {x_{n+1}^3}-11340 {{h}^{7}} {x_{n+1}^{2}}+30113 {{h}^{9}}}{9450 {h^8}}\\
c_{19}&=\frac{1120 {x_{n+1}^9}+12600 h {x_{n+1}^8}+52560 {h^2} {x_{n+1}^7}+92400 {h^3} {x_{n+1}^6}+26334 {h^4} {x_{n+1}^5}-130725 {h^5} {x_{n+1}^4}-169890 {h^6} {x_{n+1}^3}-66150 {h^7} {x_{n+1}^2}+181751 {h^9}}{226800 {h^8}}\\
c_{(10)}&=-\frac{160 {x_{n+1}^9}+1710 h {x_{n+1}^8}+6840 {h^2} {x_{n+1}^7}+11550 {h^3} {x_{n+1}^6}+2772 {h^4} {x_{n+1}^5}-16695 {h^5} {x_{n+1}^4}-21060 {h^6} {x_{n+1}^3}-8100 {h^7}{x_{n+1}^2}+22823 {h^9}}{255150{h^8}}
\end{align*}
\end{document}
答案1
放弃那些难以读懂的长分数并分割分子。
在下面的代码中我删除了所有不必要的括号。
\documentclass[a4paper,12pt]{book}
\usepackage[T1]{fontenc} % <-- new
\usepackage[inner=3.8cm, outer=1.3cm, top=2.5cm, bottom=1.2cm]{geometry}
\usepackage{amssymb,mathtools}
\begin{document}
\begin{align*}
c_{11}&=1\\
c_{12}&=-\frac{1}{2041200h^8}\bigl(
\begin{aligned}[t]
& 160 x_{n+1}^9 + 2520 h x_{n+1}^8 + 16560 h^2 x_{n+1}^7 + 58800 h^3 x_{n+1}^6 \\
& + 121842 h^4x_{n+1}^5+147735h^5x_{n+1}^4 + 98010 h^6 x_{n+1}^3 \\
& + 28350 h^7 x_{n+1}^2 - 473977 h^9 \bigr)
\end{aligned}
\\
c_{13}&=\frac{1}{113400 h^8} \bigl(
\begin{aligned}[t]
& 320 x_{n+1}^9 + 4680 h x_{n+1}^8 + 27360 h^2 x_{n+1}^7 + 78960 h^3 x_{n+1}^6 \\
& + 102564 h^4 x_{n+1}^5 - 9135 h^5 x_{n+1}^4 - 197940 h^6 x_{n+1}^3 \\
& - 237330 h^7 x_{n+1}^2 - 113400 h^8 x_{n+1} + 343921 h^9 \bigr)
\end{aligned}
\end{align*}
\end{document}
以类似的方式修复以下几行。
与使用 获得的结果进行比较\resizebox。
答案2
我不会使用 resizebox，而是使用将长分子分成两\splitfrac行mathtools：
（红线表示页面布局）
仅前三行：
\documentclass[a4paper,12pt]{book}
\usepackage[inner=3.8cm, outer=1.3cm,
top=2.5cm, bottom=1.2cm]{geometry}
\usepackage[T1]{fontenc} % <-- new
\usepackage{amssymb, mathtools}
\allowdisplaybreaks
\begin{document}
\begin{align*}
c_{11} & = 1\\
c_{12} & = -\frac{\splitfrac{160x_{n+1}^9 + 2520hx_{n+1}^8 + 16560h^2 x_{n+1}^7 + 58800h^3 x_{n+1}^6 +
121842h^4x_{n+1}^5 +}
{147735h^5x_{n+1}^4 +98010h^6x_{n+1sing}^3 +28350h^7x_{n+1}^2 - 473977h^9}}
{2041200h^8} \\[2ex]
c_{13} & = \frac{\splitfrac{320x_{n+1}^9 +4680hx_{n+1}^8 + 27360h^2x_{n+1}^7 + 78960 h^3 x_{n+1}^6 +
102564h^4x_{n+1}^5 - }
{9135h^5x_{n+1}^4 - 197940h^6x_{n+1}^3 - 237330h^7x_{n+1}^2 - 113400h^8 x_{n+1} + 343921 h^9}}
{113400 {h^8}}%\\
\end{align*}
\end{document}