\documentclass{article}
\usepackage{geometry}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{quotes,angles}
\begin{document}
\begin{center}
\begin{tikzpicture}[scale=1,cap=round]
\draw[style=help lines,step=1cm, dotted] (-0.9,-0.9) grid (9.9,7.9);
\draw[<->] (-0.9,0) -- (9.9,0) node[right] {$x$};
\draw[<->] (0,-0.9) -- (0,7.9) node[above] {$y$};
\coordinate (O) at (0,0);
\coordinate (A) at (4,3);
\coordinate (A1) at (4,0);
\coordinate (B) at (8,6);
\coordinate (B1) at (8,0);
\draw[thick,black,->,shorten >=-1.5cm] (O)--(B);
\draw[fill] (O) circle (2pt) node[below left]{$O$};
\draw[fill,blue] (A) circle (2pt) node[right=3pt] {\large $(x^{'},y^{'})$};
\node at (A) [above] {$\textcolor{blue}{P^{'}}$};
\draw[fill,red] (B) circle (2pt) node[right=3pt]{\large $(x,y)$};
\node at (B) [above]{$\textcolor{red}{P}$};
\draw[black] (4,.3)--(3.7,.3)--(3.7,0);
\draw[black] (8,.3)--(7.7,.3)--(7.7,0);
\draw[dashed,blue,thick] (A) -- (A1) node[below] {\large $A^{'}$};
\draw[dashed,red,thick] (B) -- (B1) node[below] {\large $A^{'}$};
\draw pic["\textcolor{black}{\large $\theta$}", draw=black,thick, ->, angle eccentricity=1.2, angle radius=1cm]
{angle=A1--O--B};
\end{tikzpicture}
\end{center}
\end{document}
outputs
I'm trying to finish it to look like
答案1
使用相对坐标来放置缺失的内容。由于 OP' 位于 (4,3) 方向,因此垂直向量将位于 (-3,4) 方向。
将以下行添加到您的代码中
\draw (O) ++ (-3*0.03,4*0.03) --++ (-3*0.25,4*0.25);
\draw (A) ++ (-3*0.03,4*0.03) --++ (-3*0.075,4*0.075);
\draw (B) ++ (-3*0.03,4*0.03) --++ (-3*0.25,4*0.25);
\draw[blue,<->,>=latex] (O) ++ (-3*0.07,4*0.07) -- node[midway,above] {$r^{'}$}++ (4,3);
\draw[red,<->,>=latex] (O) ++ (-3*0.2,4*0.2) -- node[midway,above] {$r$}++ (8,6);
前三行绘制黑色分隔线。比例值(0.03、0.25 等)是近似值。您可以调整它们以调整线条的位置。
完整代码:
\documentclass{article}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{quotes,angles}
\begin{document}
\begin{center}
\begin{tikzpicture}[scale=1,cap=round]
\draw[style=help lines,step=1cm, dotted] (-0.9,-0.9) grid (9.9,7.9);
\draw[<->] (-0.9,0) -- (9.9,0) node[right] {$x$};
\draw[<->] (0,-0.9) -- (0,7.9) node[above] {$y$};
\coordinate (O) at (0,0);
\coordinate (A) at (4,3);
\coordinate (A1) at (4,0);
\coordinate (B) at (8,6);
\coordinate (B1) at (8,0);
\draw[thick,black,->,shorten >=-1.5cm] (O)--(B);
\draw[fill] (O) circle (2pt) node[below left]{$O$};
\draw[fill,blue] (A) circle (2pt) node[right=3pt] {\large $(x^{'},y^{'})$};
\node at (A) [above] {$\textcolor{blue}{P^{'}}$};
\draw[fill,red] (B) circle (2pt) node[right=3pt]{\large $(x,y)$};
\node at (B) [above]{$\textcolor{red}{P}$};
\draw[black] (4,.3)--(3.7,.3)--(3.7,0);
\draw[black] (8,.3)--(7.7,.3)--(7.7,0);
\draw[dashed,blue,thick] (A) -- (A1) node[below] {\large $A^{'}$};
\draw[dashed,red,thick] (B) -- (B1) node[below] {\large $A^{'}$};
\draw pic["\textcolor{black}{\large $\theta$}", draw=black,thick, ->, angle eccentricity=1.2, angle radius=1cm]
{angle=A1--O--B};
\draw (O) ++ (-3*0.03,4*0.03) --++ (-3*0.25,4*0.25);
\draw (A) ++ (-3*0.03,4*0.03) --++ (-3*0.075,4*0.075);
\draw (B) ++ (-3*0.03,4*0.03) --++ (-3*0.25,4*0.25);
\draw[blue,<->,>=latex] (O) ++ (-3*0.07,4*0.07) -- node[midway,above] {$r^{'}$}++ (4,3);
\draw[red,<->,>=latex] (O) ++ (-3*0.2,4*0.2) -- node[midway,above] {$r$}++ (8,6);
\end{tikzpicture}
\end{center}
\end{document}