\pic使用变量时，命名对象的好方法是什么\foreach？我使用中的变量\foreach作为节点名称的一部分。如果我不使用local bounding box，则不会出现形状名称错误。如果我使用local bounding box，则会出现另一个与字段名称相关的错误。下面是我使用的代码。
\begin{center}
\begin{tikzpicture}[
pics/multisquare/.style args={#1/#2}{
code={%
\node [draw, minimum height=.4em, minimum width=.8em,
fill=#1, inner sep=0pt] (s1) {};
\node [draw, minimum height=.4em, minimum width=.8em,
fill=#2, anchor=north, inner sep=0pt] (s2) at (s1.south) {};}
},
]
\foreach \y in {0,...,4}
\pic [local bounding box=node-\y] at (0, -\y) {multisquare=red/blue};
\foreach \y in {0,...,4}
\pic [local bounding box=node-\y] at (1.6, -\y) {multisquare=red/blue};
% -----------------------------------------------------------
% code below shows an error
% \foreach \source in {0,...,4}
% \foreach \dest in {0,...,4}
% \draw [->] (node-\dest) -- (node-\source);
% -----------------------------------------------------------
% -----------------------------------------------------------
% code below does not have an error
\pic [local bounding box=node-1] at (0, 1) {multisquare=green/yellow};
\pic [local bounding box=node-2] at (0, 2) {multisquare=green/yellow};
\draw [->] (node-1) -- (node-2);
% -----------------------------------------------------------
% -----------------------------------------------------------
% code below has an error
% \pic (l3-1) at (0, 1) {multisquare=green/yellow};
% \pic (l4-1) at (0, 2) {multisquare=green/yellow};
% \draw [->] (l3-1) -- (l4-1);
% -----------------------------------------------------------
\end{tikzpicture}
\end{center}
更准确地说，我的计划是定义一个由多个形状（或节点）组合而成的新形状（或新节点）。当使用相对定位时，我想将该新形状（或新节点）用作对象。
答案1
我不完全理解你想做什么，但我认为你被困在如何\node在 a 中引用 a 的地方\pic。你可以这样做：习惯上在 a 中用 a\pic开头-（连字符减号）来命名节点，例如-s1。此外，你可以将 a 命名\pic为节点，例如像这样：
\pic (p1) at (0,1) {multisquare=green/yellow};
\pic现在，它的名称为p1，如果其中有一个名为的节点-s1，则可以使用来引用该节点p1-s1。无需使用边界框，这也可以在\foreach循环内工作。
应用于您的代码，您可以执行如下操作：
\documentclass[border=15pt]{standalone}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[
pics/multisquare/.style args={#1/#2}{
code={
\node[draw, minimum height=.4em, minimum width=.8em,
fill={#1}, inner sep=0pt] (-s1) {};
\node[draw, minimum height=.4em, minimum width=.8em,
fill={#2}, anchor=north, inner sep=0pt] (-s2) at (-s1.south) {};
}
},
]
\pic (p1) at (0,1) {multisquare={green/yellow}};
\pic (p2) at (0,2) {multisquare={green/yellow}};
\draw[->] (p1-s1) -- (p2-s2);
\foreach \i in {3,4} {
\pic (p\i) at (0,\i) {multisquare={red/blue}};
}
\draw[->] (p3-s1) -- (p4-s2);
\end{tikzpicture}
\end{document}
您也可以不使用节点，而只是在您的图形中\pic设置一些坐标：
\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[
pics/multisquare/.style args={#1/#2}{
code={
\coordinate (-north) at (0,.4em);
\coordinate (-south) at (0,-.4em);
\draw[fill=#1] (-.4em,0em) rectangle (.4em,.4em);
\draw[fill=#2] (-.4em,-.4em) rectangle (.4em,0em);
}
}
]
\pic (p1) at (0,1) {multisquare={green/yellow}};
\pic (p2) at (0,2) {multisquare={green/yellow}};
\draw[->] (p1-north) -- (p2-south);
\foreach \i in {3,4} {
\pic (p\i) at (0,\i) {multisquare={red/blue}};
}
\draw[->] (p3-north) -- (p4-south);
\end{tikzpicture}
\end{document}
如果您想使用一个节点，但不喜欢引用不同的节点名称，您可以只使用一个节点并用 填充它path picture。您也可以使用多部分节点，但我认为调整尺寸会稍微复杂一些：
\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[
multisquare/.style args={#1/#2}{
draw, minimum height=.8em, minimum width=.8em, inner sep=0pt,
path picture={
\fill[#1] (path picture bounding box.east)
rectangle (path picture bounding box.north west);
\fill[#2] (path picture bounding box.south east)
rectangle (path picture bounding box.west);
\draw (path picture bounding box.east)
-- (path picture bounding box.west);
}
}
]
\node[multisquare={green/yellow}] (p1) at (0,1) {};
\node[multisquare={green/yellow}] (p2) at (0,2) {};
\draw[->] (p1) -- (p2);
\foreach \i in {3,4} {
\node[multisquare={red/blue}] (p\i) at (0,\i) {};
}
\draw[->] (p3) -- (p4);
\end{tikzpicture}
\end{document}
与上面相同的输出。