行为举止非常古怪的病例

行为举止非常古怪的病例

如果有人能告诉我为什么下面的代码中的情况会变得如此荒谬,我会非常高兴。

\begin{align}
I^*= \begin{cases} 
0, & \left(\mathbb{E}\left[\theta_c|C=1\right] < \theta_i \ \
\text{and} \ \  \mathbb{E}\left[\max\left\{\theta_i,\theta_c\right\}|C=1\right] <
\frac{c_I}{\gamma}\right) \\ 
0, & \left(\mathbb{E}\left[\theta_c|C=1\right] \geq 
\theta_i \ \ \text{and} \ \  \mathbb{E}\left[\max\left\ 
\theta_i,\theta_c\right\}|C=1\right] < \frac{c_I}{\gamma}\right) \\ 
\left[0,1\right], & \left(\mathbb{E}\left[\theta_c|C=1\right] < \theta_i \ \ 
\text{and} \ \  \mathbb{E}\left[\max\left\{\theta_i,\theta_c\right\}|C=1\right] = 
\frac{c_I} {\gamma}\right) \\ 
\left[0,1\right], & \left(\mathbb{E}\left[\theta_c|C=1\right] \geq 
\theta_i \ \ \text{and} \ \  \mathbb{E}\left[\max\left\
{\theta_i,\theta_c\right\}|C=1\right] = \frac{c_I}{\gamma}\right) \\ 
1, \left(\mathbb{E}\left[\theta_c|C=1\right] < \theta_i \ \ \text{and} \ \  
\mathbb{E}\left[\max\left\{\theta_i,\theta_c\right\}|C=1\right] > \frac{c_I}
{\gamma}\right) \\ 
1, \left(\mathbb{E}\left[\theta_c|C=1\right] \geq \theta_i \ \ 
\text{and} \ \  \mathbb{E}\left[\max\left\{\theta_i,\theta_c\right\}|C=1\right] > 
\frac{c_I}{\gamma}\right) 
\end{cases} 
\end{align}

代码如下所示: 在此处输入图片描述 谢谢

答案1

您缺少&代码1,的最后两行:

\begin{equation}
I^*= \begin{cases} 
0, & \text{if }
\mathbb{E}[\theta_c\mid C=1] < \theta_i
\text{ and }
\mathbb{E}[\max\{\theta_i,\theta_c\} \mid C=1] < \frac{c_I}{\gamma}
\\ 
0, & \text{if }
\mathbb{E}[\theta_c \mid C=1] \geq \theta_i 
\text{ and }
\mathbb{E}[\max\{\theta_i,\theta_c\} \mid C=1] < \frac{c_I}{\gamma}
\\ 
[0,1], & \mathbb{E}[\theta_c \mid C=1] < \theta_i 
\text{ and }
\mathbb{E}[\max\{\theta_i,\theta_c\} \mid C=1] = \frac{c_I}{\gamma}
\\ 
[0,1], & \text{if }
\mathbb{E}[\theta_c \mid C=1] \geq \theta_i
\text{ and }
\mathbb{E}[\max\{\theta_i,\theta_c\} \mid C=1] = \frac{c_I}{\gamma}
\\ 
1, & \text{if }
\mathbb{E}[\theta_c \mid C=1] < \theta_i
\text{ and }
\mathbb{E}[\max\{\theta_i,\theta_c\} \mid C=1] > \frac{c_I}{\gamma}
\\
1, & \text{if }
\mathbb{E}[\theta_c \mid C=1] \geq \theta_i 
\text{ and }
\mathbb{E}[\max\{\theta_i,\theta_c\} \mid C=1] > \frac{c_I}{\gamma}
\end{cases} 
\end{equation}

请注意,我做了一些改进,即我删除了外括号,放在if每一行,删除了周围不必要的空格and(并将它们放在里面\text{...},但这不是必需的),我删除了所有虚假的\left...\right,我改为|\mid获得适当的间距。

(我希望我没有搞砸任何事情,我现在无法测试代码。)

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