![KSH while 循环导致问题](https://linux22.com/image/52231/KSH%20while%20%E5%BE%AA%E7%8E%AF%E5%AF%BC%E8%87%B4%E9%97%AE%E9%A2%98.png)
大家好,我在运行 KSH 脚本时收到此错误消息:
./file.sh:第 16 行:第 22 行语法错误:“完成”意外
我的代码如下:
#!/bin/ksh
#
count=$# #count is assigned num of parameters
num=$1 #assign parameter 1 to num
if test count -gt 9 #make sure theres only 9 numbers
then
echo "Only 9 parameters allowed"
exit
fi
echo "Number of Parameters you passed: $count"
printf "$num + \c"
sum=$1
while test $count -ge 1
shift 1 #move numbers 1 to left
num=$1 #assign new value to num
printf "num + \c"
done
((sum = sum + num))
echo "$num = $sum"
答案1
您缺少do
关键字:
while ...; do
...
done
答案2
您需要do
在以下内容之后while
:
while test $count -ge 1
do
...
done