将 PHP 脚本传递给监听 127.0.0.1:9000 的 FastCGI 服务器

Question

我的 wordpress 告诉我将 htaccess 文件更新为：

<IfModule mod_rewrite.c>
RewriteEngine On
RewriteBase /
RewriteRule ^index\.php$ - [L]
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . /index.php [L]
</IfModule>

我正在使用 nginx，我有这个，但是它不起作用：

 location / {
            root   /home/mywebsite/public;
            index  index.php index.html index.htm;

            if (!-e $request_filename) {
                        rewrite ~(.+)$ /index.php?q=$1 last;
            }
        }

Answer 1

尝试将其改为这样；

   location / {
       root   /home/mywebsite/public;
       index index.php index.html index.htm;
       try_files $uri $uri/ /index.php;

   }

http://wiki.nginx.org/HttpCoreModule#try_files

Answer 2

其运行完美。

并启用 PHP

将 PHP 脚本传递给监听 127.0.0.1:9000 的 FastCGI 服务器

    #
    location ~ \.php$ {
            fastcgi_split_path_info ^(.+\.php)(/.+)$;
    #       # NOTE: You should have "cgi.fix_pathinfo = 0;" in php.ini
    #
    #       # With php5-cgi alone:
    #       fastcgi_pass 127.0.0.1:9000;
    #       # With php5-fpm:
            fastcgi_pass unix:/var/run/php5-fpm.sock;
            fastcgi_index index.php;
            include fastcgi_params;
    }