从 cron 运行 bash 脚本时失败并出现以下错误
/bin/sh: -c: line 0: unexpected EOF while looking for matching ``'
/bin/sh: -c: line 1: syntax error: unexpected end of file
奇怪的是,当从提示符执行时,它运行完美
整个脚本
#!/bin/sh
NOW=$(date +"%b-%d-%y")
bu_PATH="/home/webserver/"
curtime=$(date)
echo ""
echo "Starting backup: $curtime"
echo ""
echo "Moving to $bu_PATH"
cd $bu_PATH
BACKUP_FILE="backup_$NOW.tgz"
echo ""
echo "The backup file will be called $BACKUP_FILE"
RUN_BACKUP="/usr/local/psa/bin/pleskbackup --server --output-file=$bu_PATH$BACKUP_FILE"
echo "Running backup...."
echo `$RUN_BACKUP`
curtime=$(date)
echo "Backup complete: $curtime"
echo ""
echo "Remove older than 7 days of files..."
ssh server '/shares/backup/webserver/cleanup.sh'
curtime=$(date)
echo ""
echo "Connecting to FTP: $curtime"
sftp -b server <<EOF
cd /shares/backup/webserver/
put $bu_PATH$BACKUP_FILE
quit
EOF;
curtime=$(date)
echo "FTP Transfer Complete: $curtime"
echo ""
echo "Cleaning up Local backups"
sh /home/cleanup.sh
echo ""
echo "Clean up log files"
find /home/webserver/logs/*.log -mtime +7 -exec rm {} \;
echo "Job Complete"
这是 crontab 条目
/home/backup.sh > /home/webserver/logs/BackupLog-`date +%m%d%y`.log
谢谢 Rob
答案1
如果在 crontab 中使用反引号 (`),则需要转义 crontab 条目中的 % 符号。
像这样:
/home/backup.sh > /home/webserver/logs/BackupLog-`date +\%m\%d\%y`.log
如果您不对其进行转义,它们将被视为换行符。
答案2
您的 EOF 看起来不对,EOF;与您预期的 EOF 不匹配(删除分号)。
[hlinden@dolphin tmp]$ cat dog.sh /bin/bash #!/bin/bash 猫 <<EOF 狗 猫 结束语; [hlinden@dolphin tmp]$ sh dog.sh dog.sh:第 6 行:警告:第 3 行的此处文档由文件末尾分隔(需要“EOF”) 狗 猫 结束语; [hlinden@dolphin tmp]$ sed -is/\;// dog.sh [hlinden@dolphin tmp]$ sh dog.sh 狗 猫 [hlinden@dolphin tmp]$