我有一个有很多子文件夹的文件夹
- D:\数据\子文件夹1
- D:\数据\子文件夹2
- D:\数据\子文件夹3
- D:\数据\子文件夹4
- D:\数据\子文件夹5
- ...
我需要像这样为每个子文件夹创建三个活动目录组。
- FS_Data-子文件夹1_读取
- FS_数据-子文件夹1_更改
- FS_Data-子文件夹1_完整
完成后,我必须映射文件夹、Activedirectory 组和权限。
设置权限是最难的部分。这就是我取得的进展。我不知道如何将组绑定到权限,然后将其应用到文件夹。
$SharePath = "\\fs\data\"
$FSGroupPath = "OU=GROUPS,OU=Data,DC=DOMAIN,DC=LOCAL"
Get-ChildItem $SharePath | ForEach-Object {
$GroupNameRead = "FS_Data-" + $_ + "_Read"
$GroupNameChange = "FS_Data-" + $_ + "_Change"
$GroupNameFull = "FS_Data-" + $_ + "_Full"
New-ADGroup -Name $GroupNameRead -DisplayName $GroupNameRead -GroupScope DomainLocal -GroupCategory Security -Path $FSGroupPath -Description "Ger Läs Rättigheter till sökväg: FS\Data\$_"
New-ADGroup -Name $GroupNameChange -DisplayName $GroupNameChange -GroupScope DomainLocal -GroupCategory Security -Path $FSGroupPath -Description "Ger Ändra Rättigheter till sökväg: FS\Data\$_"
New-ADGroup -Name $GroupNameFull -DisplayName $GroupNameFull -GroupScope DomainLocal -GroupCategory Security -Path $FSGroupPath -Description "Ger Fulla Rättigheter till sökväg: FS\Data\$_"
$set_Group = $GroupNameFull
$set_rights = Modify
$acl = Get-Acl $SharePath
$permission = $set_user,$set_rights,"Allow"
$accessRule = New-Object System.Security.AccessControl.FileSystemAccessRule $permission
$acl.SetAccessRule($accessRule)
$acl | Set-Acl $SharePath
}
答案1
看看这是 Don Jones 的例子帮助您:您基本上从文件夹中获取现有的 acl 对象,向其添加新规则 (SetAccessRule),并且该规则包含主体(用户或组、权限以及是允许还是拒绝)。然后使用 set-acl 将更新的 aclobject 应用于文件/文件夹。
#ChangeACL.ps1
$Right="FullControl"
#The possible values for Rights are
# ListDirectory, ReadData, WriteData
# CreateFiles, CreateDirectories, AppendData
# ReadExtendedAttributes, WriteExtendedAttributes, Traverse
# ExecuteFile, DeleteSubdirectoriesAndFiles, ReadAttributes
# WriteAttributes, Write, Delete
# ReadPermissions, Read, ReadAndExecute
# Modify, ChangePermissions, TakeOwnership
# Synchronize, FullControl
$StartingDir=Read-Host "What directory do you want to start at?"
$Principal=Read-Host "What security principal do you want to grant" `
"$Right to? `n Use format domain\username or domain\group"
#define a new access rule.
#note that the $rule line has been artificially broken for print purposes.
#it needs to be one line. the online version of the script is properly
#formatted.
$rule=new-object System.Security.AccessControl.FileSystemAccessRule($Principal,$Right,"Allow")
foreach ($file in $(Get-ChildItem $StartingDir -recurse)) {
$acl=get-acl $file.FullName
#Add this access rule to the ACL
$acl.SetAccessRule($rule)
#Write the changes to the object
set-acl $File.Fullname $acl
}
答案2
当您在 cmdlet-PassThru
上指定参数时New-ADGroup
,它会返回新组。您返回的 ADGroup 对象包含一个 SID 属性,您可以使用它来传递IdentityReference
访问规则:
$readGroup = New-ADGroup -Name $GroupNameRead -DisplayName $GroupNameRead -GroupScope DomainLocal -GroupCategory Security -Path $FSGroupPath -Description "Ger Läs Rättigheter till sökväg: FS\Data\$_" -PassThru
if(-not($readGroup)) # Make sure it got created, if not, handle the error
{
# Error handling in here
}
else
{
$accessRule = New-Object System.Security.AccessControl.FileSystemAccessRule($readGroup.SID,Read,Allow)
}