学习脚本编写的基础知识,我有这行代码:
#!/bin/sh
if [ $# -ne 1]
then
echo "Please provide one directory to search"
echo "Example usage: something.sh directory_name"
exit 1
fi
但是,当我运行此命令时,我收到错误,if: Expression Syntax.
我在这里到底缺少什么?下一个 if 语句也给了我同样的错误:(我希望它检查变量是否是目录
if [ !-d $1 ]
then
echo "$1: Invalid Directory. Aborting Script."
exit 1
fi
完整脚本以防有帮助:
#!/bin/sh
if [ $# -ne 1 ]
then
echo "Please provide one directory to search"
echo "Example usage: something directory_name"
exit 1
fi
if [ ! -d $1 ]
then
echo "$1: Invalid Directory. Aborting Script."
exit 1
fi
cd "$1"
read=0
write=0
exe=0
numFiles=0
numDir=0
for filename in *
do
if [ -r filename ]
then
`expr $read + 1`
fi
if [ -x filename ]
then
`expr $exe + 1`
fi
if [ -w filename ]
then
`expr $write + 1`
fi
if [ -f filename ]
then
`expr $numFiles + 1`
fi
done
for dir in */
do
if [ -r dir ]
then
`expr $read + 1`
fi
if [ -x dir ]
then
`expr $exe + 1`
fi
if [ -w dir ]
then
`expr $write + 1`
fi
if [ -d dir ]
then
`expr $numDir + 1`
fi
done
total=`expr $numDir + $numFiles`
echo "In the directory $1"
echo " Number of directories : $numDir"
echo " Number of files : $numFiles"
echo " Number of readable items : $read"
echo " Number of writable : $write"
echo " Number of executable items: $exe"
echo "-------------------------------"
echo "Total number of items: $total"
更新:以防万一有人偶然发现这一点,我在#!/bin/bash
导致 if 表达式错误之前有标题注释
答案1
你有很多问题。这是工作版本。您需要使用 $ 来表示变量的值($filename
而不是filename
),并且需要将表达式的结果分配给变量,而不是仅仅调用表达式(read=expr $read + 1
而不是expr $read + 1
)。
#!/bin/bash
if [ $# -ne 1 ]
then
echo "Please provide one directory to search"
echo "Example usage: assignment4.sh directory_name"
exit 1
fi
if [ ! -d "$1" ]
then
echo "$1: Invalid Directory. Aborting Script."
exit 1
fi
cd "$1"
read=0
write=0
exe=0
numFiles=0
numDir=0
for filename in *
do
if [ -r "$filename" ]
then
read=`expr $read + 1`
fi
if [ -x filename ]
then
exe=`expr $exe + 1`
fi
if [ -w "$filename" ]
then
write=`expr $write + 1`
fi
if [ -f "$filename" ]
then
numFiles=`expr $numFiles + 1`
fi
done
for dir in */
do
if [ -r "$dir" ]
then
read=`expr $read + 1`
fi
if [ -x "$dir" ]
then
exe=`expr $exe + 1`
fi
if [ -w "$dir" ]
then
write=`expr $write + 1`
fi
if [ -d "$dir" ]
then
numDir=`expr $numDir + 1`
fi
done
total=`expr $numDir + $numFiles`
echo "In the directory $1"
echo " Number of directories : $numDir"
echo " Number of files : $numFiles"
echo " Number of readable items : $read"
echo " Number of writable : $write"
echo " Number of executable items: $exe"
echo "-------------------------------"
echo "Total number of items: $total"
$ ./script.sh
Please provide one directory to search
Example usage: something.sh directory_name
$ ./script.sh /home/username
In the directory /home/username
Number of directories : 8
Number of files : 104
Number of readable items : 120
Number of writable : 120
Number of executable items: 8
-------------------------------
Total number of items: 112
答案2
你缺少的是空格。
这有效:
if [ $# -ne 1 ]
then
echo "One argument needed"
exit 1
fi
同样地:
if [ ! -d $1 ]