如何在 ansible 剧本中正确转义反斜杠?
我正在尝试搜索并替换密码中的反斜杠,但我甚至无法在 regex_replace jinja2 过滤器中将反斜杠添加为字符串。我使用的是 ansible 版本 2.1.1.0。
以下是该问题的一个例子:
$ cat jinja2-escape-test.yml
---
- hosts: localhost
gather_facts: no
vars:
password: '\Udl5DoQfa3Uy_:1sbcE'
tasks:
- debug: var=password
- name: Escape root password - working
set_fact: "password_escaped={{ password | regex_replace ('U','\\X') }}"
- name: Escape root password - not working
set_fact: "password_escaped={{ password | regex_replace ('U','\\') }}"
- debug: msg=password_escaped={{ password_escaped }}
# vim:et:sw=2:ts=2:sts=2:
$ ansible-playbook jinja2-escape-test.yml
ERROR! failed at splitting arguments, either an unbalanced jinja2 block or quotes: password_escaped={{ password | regex_replace ('U','\') }}
The error appears to have been in '/home/mot/build-dashboards/jinja2-escape-test.yml': line 15, column 5, but may
be elsewhere in the file depending on the exact syntax problem.
The offending line appears to be:
- name: Escape root password - not working
^ here
答案1
您在这里混合了语法样式,并且引用设置错误:
- name: Escape root password - working
set_fact: "password_escaped={{ password | regex_replace ('U','\\X') }}"
应该是:
- name: Escape root password - working
set_fact:
password_escaped: "{{ password | regex_replace ('U','\\X') }}"
或者:
- name: Escape root password - working
set_fact: password_escaped="{{ password | regex_replace ('U','\\X') }}"
你可能想检查一下引用比 regex_replace 更适合您的需求。使用方式如下:
- name: Escape root password - working
set_fact:
password_escaped: "{{ password | quote }}"