我有一个自己编写的 Python 脚本。当我运行 ./myscript.py 时，它按预期完美运行，没有出错，并持续运行数天，直到我手动将其关闭。
我还为我的 Python 脚本创建了一个 SystemD 服务。但是，运行该服务时，每隔一轮就会中途出错。SystemD 重新启动脚本，它在 1 轮中运行正常，但在中途出错。
以下是 journalctl -xe -f 的错误：
Jul 05 16:04:35 glas-dev systemd[1]: magewelk.service: Start
operation timed out. Terminating.
Jul 05 16:04:35 glas-dev magewelk.py[9685]:
Jul 05 16:04:35 glas-dev systemd[1]: magewelk.service: Main process
exited, code=dumped, status=3/QUIT
Jul 05 16:04:35 glas-dev systemd[1]: Failed to start Data collector
Magewell to Elasticsearch.
-- Subject: Unit magewelk.service has failed
-- Defined-By: systemd
-- Support: http://lists.freedesktop.org/mailman/listinfo/systemd-
devel
--
-- Unit magewelk.service has failed.
--
-- The result is failed.
Jul 05 16:04:35 glas-dev systemd[1]: magewelk.service: Unit entered
failed state.
Jul 05 16:04:35 glas-dev systemd[1]: magewelk.service: Failed with
result 'core-dump'.
Jul 05 16:04:35 glas-dev systemd[1]: magewelk.service: Service hold-
off time over, scheduling restart.
Jul 05 16:04:35 glas-dev systemd[1]: Stopped Data collector Magewell
to Elasticsearch.
-- Subject: Unit magewelk.service has finished shutting down
-- Defined-By: systemd
-- Support: http://lists.freedesktop.org/mailman/listinfo/systemd-
devel
--
-- Unit magewelk.service has finished shutting down.
Jul 05 16:04:35 glas-dev systemd[1]: Starting Data collector Magewell
to Elasticsearch...
-- Subject: Unit magewelk.service has begun start-up
-- Defined-By: systemd
-- Support: http://lists.freedesktop.org/mailman/listinfo/systemd-
devel
--
-- Unit magewelk.service has begun starting up.
magewelk.service文件如下：
[Unit]
Description=Data collector Magewell to Elasticsearch
After=syslog.target
[Service]
WorkingDirectory=/opt/labglas_streamer
ExecStartPre=/bin/bash -c 'chown -R charter:www-data
/opt/labglas_streamer'
ExecStart=/opt/labglas_streamer/magewelk.py
Restart=always
KillSignal=SIGQUIT
Type=notify
StandardError=syslog
NotifyAccess=all
[Install]
WantedBy=multi-user.target
该脚本是单线程的，带有错误捕获功能。我没有从该脚本中收到任何错误。
这是在 Ubuntu 16.04.2 LTS 服务器上。我观察了服务崩溃时的内存、网络连接、处理器，没有发现任何异常。
答案1
您可能希望使用“简单”作为类型，而不是“通知”。仅当您的 Python 脚本知道如何通知 systemd 时，通知才有效。