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grep 在 bash 脚本中导致 EXIT 陷阱

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grep 在 bash 脚本中导致 EXIT 陷阱

当使用 bash 版本 3.2 在 OSX 中运行以下脚本时

#!/bin/sh

set -e
function _trap_exit {
   echo "this is a triggered trap..."
}

trap _trap_exit EXIT

/usr/sbin/ioreg -w0 -l | grep ExternalChargeCapable | grep -q No

echo "Final statement"

我触发了一个陷阱。但是，如果我将最终的 grep 语句更改为“是”，grep -q Yes则不会触发陷阱。

知道为什么会发生这种情况以及如何阻止它吗？为什么 grep 的退出代码会导致陷阱被触发？

答案1

从 Bash 手册页...

-e      Exit immediately if a simple command (see SHELL GRAMMAR above) exits with a non-
        zero  status.   The shell does not exit if the command that fails is part of the
        command list immediately following a while or until keyword, part of the test in
        an  if  statement,  part of a && or || list, or if the command's return value is
        being inverted via !.  A trap on ERR, if  set,  is  executed  before  the  shell
        exits.

[/傻瓜]

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