我有一个数据集，如下所示：
chr1 HAVANA gene 69091 70008 . + . gene_id "ENSG00000186092.4"; transcript_id "ENSG00000186092.4"; gene_type "protein_coding"; gene_status "KNOWN"; gene_name "OR4F5"; transcript_type "protein_coding"; transcript_status "KNOWN"; transcript_name "OR4F5"; level 2; havana_gene "OTTHUMG00000001094.1";
chr1 ENSEMBL gene 134901 139379 . - . gene_id "ENSG00000237683.5"; transcript_id "ENSG00000237683.5"; gene_type "protein_coding"; gene_status "KNOWN"; gene_name "AL627309.1"; transcript_type "protein_coding"; transcript_status "KNOWN"; transcript_name "AL627309.1"; level 3;
chr1 HAVANA gene 367640 368634 . + . gene_id "ENSG00000235249.1"; transcript_id "ENSG00000235249.1"; gene_type "protein_coding"; gene_status "KNOWN"; gene_name "OR4F29"; transcript_type "protein_coding"; transcript_status "KNOWN"; transcript_name "OR4F29"; level 2; havana_gene "OTTHUMG00000002860.1";
chr1 HAVANA gene 621059 622053 . - . gene_id "ENSG00000185097.2"; transcript_id "ENSG00000185097.2"; gene_type "protein_coding"; gene_status "KNOWN"; gene_name "OR4F16"; transcript_type "protein_coding"; transcript_status "KNOWN"; transcript_name "OR4F16"; level 2; havana_gene "OTTHUMG00000002581.1";
chr1 ENSEMBL gene 738532 739137 . - . gene_id "ENSG00000269831.1"; transcript_id "ENSG00000269831.1"; gene_type "protein_coding"; gene_status "NOVEL"; gene_name "AL669831.1"; transcript_type "protein_coding"; transcript_status "NOVEL"; transcript_name "AL669831.1"; level 3;
如果可能的话，我想使用 awk 删除 $5 和 $4 之间的差异小于 2000 的基因。尽管 sed 也是可以接受的。
所以它返回以下内容：
chr1 ENSEMBL gene 134901 139379 . - . gene_id "ENSG00000237683.5"; transcript_id "ENSG00000237683.5"; gene_type "protein_coding"; gene_status "KNOWN"; gene_name "AL627309.1"; transcript_type "protein_coding"; transcript_status "KNOWN"; transcript_name "AL627309.1"; level 3;
谢谢。
答案1
awk '$5-$4 >= 2000' file
如果 5 美元总是大于 4 美元