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Linux 启动 bash 问题：命令替换问题

tag-icon • tag-icon linux bash command-substitution
Linux 启动 bash 问题：命令替换问题

我尝试在我的环境中启动一个新的 shell，但bash命令有问题：

$ bash
bash: command substitution: line 1: syntax error near unexpected token `then'
'ash: command substitution: line 1: `print -n "`logname`@`hostname`:$(tput sgr0)";if [[ "${PWD#$HOME}" != "$PWD" ]] then; print -n "~${PWD#$HOME}"; else; print -n "$PWD";fi;print "
bash: command substitution: line 1: syntax error near unexpected token `then'
bash: command substitution: line 1: `print -n "`logname`@`hostname`:$(tput sgr0)";if [[ "${PWD#$HOME}" != "$PWD" ]] then; print -n "~${PWD#$HOME}"; else; print -n "$PWD";fi;print "'

然后我就无法逃脱

$ ")^C
bash: command substitution: line 2: syntax error near unexpected token `then'
'ash: command substitution: line 2: `print -n "`logname`@`hostname`:$(tput sgr0)";if [[ "${PWD#$HOME}" != "$PWD" ]] then; print -n "~${PWD#$HOME}"; else; print -n "$PWD";fi;print "
bash: command substitution: line 1: syntax error near unexpected token `then'
bash: command substitution: line 1: `print -n "`logname`@`hostname`:$(tput sgr0)";if [[ "${PWD#$HOME}" != "$PWD" ]] then; print -n "~${PWD#$HOME}"; else; print -n "$PWD";fi;print "'

并且必须留下外壳 - 我想这意味着它确实打开了一个子外壳。

它打开的外壳有奇怪的行为，因为对于我输入的每个命令，它都会重复上述错误的四行。

我看了看，~/.bashrc但它唯一做的就是umask 0022。

-x没有给我太多关于我的问题的信息

$ bash -x
+ umask 0022
++ tput bold
bash: command substitution: line 1: syntax error near unexpected token `then'
... same error

这可以链接到评论行中的'内容吗：/ect/bashrc

if ! shopt -q login_shell ; then # We're not a login shell
   # Need to redefine pathmunge, it get's undefined at the end of /etc/profile
   pathmunge () {
     case ":${PATH}:" in
        *:"$1":*)
            ;;
        *)
            if [ "$2" = "after" ] ; then
                PATH=$PATH:$1
            else
                PATH=$1:$PATH
            fi
     esac
   }

我应该从这里看向哪里？我应该要求/etc/bashrc以任何方式修复/修改吗？

编辑

正如有人建议的那样，这可能来自我的~/.profile吗？

export PS1='$(tput bold)$(print -n "`logname`@`hostname`:$(tput sgr0)";if [[ "${PWD#$HOME}" != "$PWD" ]] then; print -n "~${PWD#$HOME}"; else; print -n "$PWD";fi;print "\n$ ")'
trap 1 2 3

PATH=$PATH:$HOME/bin

export PATH
export HTTPD_HOME=/pvar/product/httpd

        export EDITOR=/bin/vi
        export FCEDIT=/bin/vi
        export VISUAL=/bin/vi
        export HISTSIZE=5000
        export TMOUT=0

任何帮助表示赞赏，谢谢。

答案1

我必须更改我的.profile以修复构建提示的行（PS1）：

export PS1='$(tput bold)$(print -n "`logname`@`hostname`:$(tput sgr0)";if [[ "${PWD#$HOME}" != "$PWD" ]] then; print -n "~${PWD#$HOME}"; else; print -n "$PWD";fi;print "\n$ ")'

成为

export PS1='$(tput bold)$(echo "`logname`@`hostname`:$(tput sgr0)" ; \
  if [[ "${PWD#$HOME}" != "$PWD" ]]; \
  then echo "~${PWD#$HOME}"; \
  else echo "${PWD}"; fi; echo "$ ")'

现在我想找到一种方法来避免echo跳过一行（我必须替换print为，echo因为 bash 默认情况下不处理print）。

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