谁能详细解释一下下面两个命令正则表达式

谁能详细解释一下下面两个命令正则表达式

以下两个命令用于计算文本文件中第二列的非零整数的数量。谁能详细解释一下正则表达式。

grep -c '^[^,]*,[^0][^,]*,' < myfile.txt
sed '/^[^,]*,0,.*/d' < myfile.txt | sed -n '$='

答案1

第一个正则表达式搜索包含以下内容的任何行:

'^        - start of line, followed by
 [^,]*    - 0 or more non-comma characters, followed by
 ,        - a comma, followed by
 [^0]     - any single character other than a zero, followed by
 [^,]*    - 0 or more non-comma characters, followed by
 ,'       - a comma

grep -c 统计匹配行数

第二个正则表达式匹配

'/        (the start of the regex)
 ^        - start of line, followed by
 [^,]*    - 0 or more non-comma characters, followed by
 ,0,      - a comma then a zero then a comma, followed by
 .*       - 0 or more other characters
 /d'      (the end of the regex -- delete the lines matching the preceding expression)

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