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Bash：根据 y 列中的值计算 x 列中值的出现次数

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Bash：根据 y 列中的值计算 x 列中值的出现次数

我有一个像这样的字符串。

data = "state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp

state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp

state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp 

state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp

state:: 2 caller_contact:: sip:[email protected]:5080;transport=udp 

state:: 2 caller_contact:: sip:[email protected]:5080;transport=udp 

state:: 1 caller_contact:: sip:[email protected]:5080;transport=udp"

我需要编写一个 bash 脚本来计算每个 IP 例如 192.168.26 具有状态 4 或状态 2 的次数。（该字符串不包含“/n”）

我无法解析该字符串并根据每个 IP 计算值。

答案1

我不确定这是否适用于您可能拥有的每种可能的组合，但它适用于您提供的小样本：

sed  "1,\$s/state/\nstate/g" file | grep state > NewFile
for IPADDR in $(cat NewFile | cut -d"@" -f2|cut -d":" -f1|sort -n|uniq);do
  for STATE in 2 4 ;do
    LineCount=$(grep "${IPADDR}" NewFile |grep "state:: ${STATE}"| wc -l)
    echo "For IP address ${IPADDR}, status:: ${STATE} lines count is ${LineCount}"
  done
done | grep -v "is 0"$

您可以在 for 循环中添加任意多个不同的 STATE 数字

基本上，您在每次出现字符串之前插入一个新行字符，state从而形成大数据块，并将其分成多行。

答案2

查找唯一的 IP 并计算每个状态 4 或 2

for addr in $(grep -o '@[^:]\+' file | sort -u); do 
    echo -n ${addr#@}:\ 
    grep -c ":: [24].*${addr#@}" file
done

或者使用 awk 执行任务

awk -F '[: @;=]+' '
    $2 ~ /^[24]$/{
        count[$6]++
        }
    END {
        for(i in count)
            print(i, count[i])
        }
    ' file

答案3

这是我的小怪物。

#!/bin/bash 
# monsterr.sh

if [ -z "$1" ] ; then
    printf "%s\n" "Syntax error."
    exit 2
fi

data="$1"

tmp=tmp$$
mkdir $tmp

parse() {
    state=
    ip=
    i=0
    while read l; do
        ((i++))
        if [ $(($i%2)) -eq 0 ]; then
            if [ $(($i%4)) -eq 2 ]; then
                state=$l
            else
                IFS=: read x ip x < <(printf %s $l)
                IFS=@ read x ip < <(printf %s $ip)
                printf "%s\n" $state >> "$tmp/$ip"
            fi
        fi
    done <  <(printf "%s\n" $data)
}


report() {
    cd $tmp
    for f in * ; do
        declare -a count
        printf "IP: %s\n" $f
             while read s ; do
                ((count[$s]++))
            done < $f
        for s in ${!count[@]}; do
            printf "State: %s, count: %s\n" $s ${count[$s]}
        done
        printf '\n'
        unset count
    done
    cd - 2 > /dev/null
}

parse
report

rm -r $tmp

用法：

$ data="state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp state:: 4 caller_contact:: sip:[email protected]:5080;transport=udp state:: 2 caller_contact:: sip:[email protected]:5080;transport=udp  state:: 2 caller_contact:: sip:[email protected]:5080;transport=udp state:: 1 caller_contact:: sip:[email protected]:5080;transport=udp"
$ ./monsterr.sh "$data"
IP: 192.168.10.01
State: 4, count: 1

IP: 192.168.10.03
State: 4, count: 1

IP: 192.168.10.07
State: 1, count: 1

IP: 192.168.10.11
State: 2, count: 1
State: 4, count: 1

IP: 192.168.10.26
State: 2, count: 1
State: 4, count: 1

答案4

grep您想要处理的行，可以使用sed.sed使用 、排序和计数从行中获取 2 个子字符串：

sed -n '/state:: [24] .*@/ s/.*:: \([24]\)[^@]*@\([^:]*\).*/State \1 IP \2/p' file |
 sort | uniq -c | sort -n

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