![if语句麻烦](https://linux22.com/image/101421/if%E8%AF%AD%E5%8F%A5%E9%BA%BB%E7%83%A6.png)
我编写了以下脚本:
#!/bin/bash
SINGLE=`cut -c 7-13 Data.txt`
cd ../FASTA_SEC_EDITED/
for i in ${SINGLE}; do
if [[ -r "${i}_Forward_Trimmed.fa" && -r ../REVERSE_COMP/"${i}_Reverse_RevComp.fa"]]
then
cp ${i}_Forward_Trimmed.fa ../Aling/Input_Muscle/${i}_Input.fa >> ../REVERSE_COMP/${i}_Reverse_RevComp.fa
usr/bin/muscle3.8.31_i86linux64 -in ../Aling/Input_Muscle/${i}_Input.fa -out ../Align/${i}_CONSENSUS.fa
else
echo "Does not exist"
fi
done
但是 if 语句似乎有问题。Bash 返回以下错误:
muscle_test.sh: line 8: syntax error in conditional expression
muscle_test.sh: line 9: syntax error near `then'
muscle_test.sh: line 9: ` then'
我一直在考虑在 of 中编写一个 AND 运算符,但似乎没问题,我不确定那里出了什么问题。任何想法?
谢谢
答案1
看来您忘记了关闭大括号之前的空格。应该是这样
if [[ -r "${i}_Forward_Trimmed.fa" && -r ../REVERSE_COMP/"${i}_Reverse_RevComp.fa" ]]