如何使用 grep 在文本文件中搜索包含列表中所有单词且没有特定顺序的行？

Question

我们如何使用grep来获取包含一组单词的行，而词序不重要，尽管应该包含所有单词在搜索中提到过吗？

我已经通过分阶段搜索（使用管道、将输出保存在临时文件中并再次搜索）完成了此操作，但我想知道是否可以在一次尝试中完成此操作。

以下是一个示例；我想在下面的行中搜索包含以下内容的行样本，字，列表：

it's a sample test file for a list of words.
list of words without a specific order, it's a sample.
line with no search keyword here.
list the sample files.
something completely different.

并得到这个结果：

it's a sample test file for a list of words.
list of words without a specific order, it's a sample.

Answer 1

简单的方法是多次调用grep：

grep sample testfile.txt | grep words | grep list

演示：

echo -e "it's a sample test file for a list of words.\nlist of words without a specific order, it's a sample. \nline with no search keyword here. \nlist the sample words. \nsomething completely different." | grep sample | grep words | grep list
it's a sample test file for a list of words.
list of words without a specific order, it's a sample. 
list the sample words. 

Answer 2

您可以将前瞻与 Perl-regex 结合使用 ( -P)：

grep -P '(?=.*list)(?=.*words)(?=.*sample)'

---

例子：

echo "it's a sample test file for a list of words.
list of words without a specific order, it's a sample.
line with no search keyword here.
list the sample words.
sample line with only two of the keywords inside.
something completely different." \
| grep -P '(?=.*list)(?=.*words)(?=.*sample)'

it's a sample test file for a list of words.
list of words without a specific order, it's a sample.
list the sample words.

（通过）

---

使用agrep( sudo apt install agrep) 你可以链接多个模式：

agrep "sample;words;list"

（通过）