如何忽略键盘上输入的特定字符？

Question

我的笔记本电脑的键盘出现故障，因此每当我按下空格键时，计算机就会获得输入，就好像我同时按下了空格键和向下翻页键一样。

我尝试使用xev来找出要通过哪个字符键码来禁用它，xmodmap -e 'keycode NUMBER = NoSymbol'但仍然无法正常工作。

我想要某种方法让操作系统完全忽略翻页按钮被触发的事实。

xev
KeyPress event, serial 37, synthetic NO, window 0x2e00001,
    root 0x178, subw 0x0, time 16645657, (-273,111), root:(415,310),
    state 0x10, keycode 117 (keysym 0xff56, Next), same_screen YES,
    XLookupString gives 0 bytes: 
    XmbLookupString gives 0 bytes: 
    XFilterEvent returns: False

KeyPress event, serial 37, synthetic NO, window 0x2e00001,
    root 0x178, subw 0x0, time 16645658, (-273,111), root:(415,310),
    state 0x10, keycode 65 (keysym 0x20, space), same_screen YES,
    XLookupString gives 1 bytes: (20) " "
    XmbLookupString gives 1 bytes: (20) " "
    XFilterEvent returns: False

因此我尝试过sudo xmodmap -e 'keycode 117 = NoSymbol'，而且以前sudo xmodmap -e 'keycode 117 = 0x0000'如果我这样做，我可以让 xev 输出更改为以下内容：

xev
KeyPress event, serial 37, synthetic NO, window 0x2e00001,
    root 0x178, subw 0x0, time 16645657, (-273,111), root:(415,310),
    state 0x10, keycode 117 (keysym 0x0, NoSymbol), same_screen YES,
    XLookupString gives 0 bytes: 
    XmbLookupString gives 0 bytes: 
    XFilterEvent returns: False

KeyPress event, serial 37, synthetic NO, window 0x2e00001,
    root 0x178, subw 0x0, time 16645658, (-273,111), root:(415,310),
    state 0x10, keycode 65 (keysym 0x20, space), same_screen YES,
    XLookupString gives 1 bytes: (20) " "
    XmbLookupString gives 1 bytes: (20) " "
    XFilterEvent returns: False

但笔记本电脑似乎仍像以前一样运行，并且仍会触发向下翻页按钮。我使用的是搭载 Ubuntu 18.04 的联想 Thinkpad T560