如何在 Linux 中使用“ls -al”移动文件?

如何在 Linux 中使用“ls -al”移动文件?

如何编写脚本根据上次修改日期将文件从一个目录复制到另一个目录?

ls -al

-rw-r--r-- 1 用户 用户 100 2011-05-二十六12:33ABC1234_封面_10344000_2011-05.doc

我到底想要做的是,使用上面 ls -al 的粗体部分结果ABC1234_frontcover_10344000_2011-05.doc将文件复制到/home/abcd/ABC1234/2011-05/26/

date -r $file +%m应该有某种方法可以使用和的值来实现basename *.doc | awk -F_ '{print $1}'。帮帮我,怎么做?

答案1

我刚刚花了一些时间尝试这一点并得出了以下脚本:

#!/bin/bash
# set folder where files are located
SOURCE_FOLDER=/path/to/source

# define folder to which the files have to be copied
TARGET_FOLDER=/home/abcd

# ####
cd "${SOURCE_FOLDER}"
for FILE in *; do
    # everything which is not a normal file
    if [ ! -f "${FILE}" ]; then
        echo "Skipping non-file: '${FILE}'"
        continue
    fi

    # extract data from file structure
    FILE_DATE=$(date -r "$FILE" '+%Y-%m')
    FILE_DAY=$(date -r "$FILE" '+%d')
    FILE_PREFIX=${FILE%%_*}

    # skip files which do not match the naming convention
    if [ "${FILE_PREFIX}" = "" -o "${FILE_PREFIX}" = "${FILE}" ]; then
        echo "Skipping file with wrong naming: '${FILE}'"
        continue
    fi

    # create target folder
    TARGET="${TARGET_FOLDER}/${FILE_PREFIX}/${FILE_DATE}/${FILE_DAY}"
    echo "Copy '$FILE' to ${TARGET}"
    mkdir -p "${TARGET}"
    cp "$FILE" "$TARGET"
done

它还涵盖了一些特殊情况和概率检查。

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