如何在为上下文菜单编写 shell 命令时仅获取文件的扩展名

Question

例如，如果键入，cmd.exe echo %1它会显示所选文件的文件名和扩展名。但我想要做的只是获取所选文件的扩展名。

有人知道怎么做吗？

Answer 1

cmd.exe echo %~x1

%*      return the remainder of the command line starting at the first command line   argument (in Windows NT 4, %* also includes all leading spaces)
%~dn    return the drive letter of %n (n can range from 0 to 9) if %n is a valid path or file name (no UNC)  
%~pn    return the directory of %n if %n is a valid path or file name (no UNC)  
%~nn    return the file name only of %n if %n is a valid file name  
%~xn    return the file extension only of %n if %n is a valid file name  
%~fn    return the fully qualified path of %n if %n is a valid file name or directory 

来源

Answer 2

您可以使用扩展属性在 Powershell 中轻松执行此操作。

举个例子（尽管还有更多方法可以实现这一点：

Get-ChildItem | select Extension

在 cmd.exe 中：

for %i in (*.*) do echo "%~xi"