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Powershell - 在单个表中显示匹配的自定义对象属性

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Powershell - 在单个表中显示匹配的自定义对象属性

我在脚本输出以我希望的方式显示信息时遇到了麻烦。我想在一个表下查看每个生成的自定义对象的匹配属性（对象是在 foreach 循环中生成的，因此它们始终具有完全相同的属性），而不是像下面的脚本当前所做的那样为每个对象创建一个新表。此脚本创建对象的方式可以实现吗？如果可以，该怎么做？

function Get-Uptime
{
[CmdletBinding()]
Param
(
    [Parameter(ValueFromPipeline=$true,
               Position=0)]
    [String[]]$ComputerName = $env:COMPUTERNAME
)

Begin {}
Process {
   foreach ($computer in $ComputerName) {
       $ComputerObject = [Ordered]@{"Computer Name" = $computer
                                    "Start Time" = $null
                                    "Uptime (Days)" = $null
                                    "Status" = $null
                                    "May Need Patched?" = $null}
       $IsOnline = Test-Connection -ComputerName $Computer -Quiet
       if ($IsOnline = $true) {
           Try { 
           #Collect information about each computer
           $WMIObject = Get-WMIObject -Class Win32_OperatingSystem -ComputerName $computer
           #Convert LastBootUpTime to readable date/time
           $ComputerObject.'Start Time' = $WMIObject.ConvertToDateTime($WMIObject.LastBootUpTime)
           #Convert LocalDateTime to readable date/time
           $ComputerObject.Uptime = $WMIObject.ConvertToDateTime($WMIObject.LocalDateTime)
           #Collect the number of days that have elapsed between
           $TimeElapsed = New-TimeSpan -Start $ConvertedBootUpTime -End $ConvertedLocalTime
           $ComputerObject.'Uptime (Days)' = [Math]::Round($TimeElapsed.TotalDays,1) 
           $ComputerObject.'May Need Patched?' = If ($ComputerObject.'Uptime (Days)' -ge "30"){$True} Else{$False}
           $ComputerObject.Status = "Online"
           }
           Catch {
           Write-Error "Unable to gather uptime for $Computer"
           $ComputerObject.Status = "Error"
           }
       }
       else {
           Write-Error "Computer $Computer is either non-existant or offline"
           $ComputerObject.Status = "Offline"
       }
       [PSCustomObject]$ComputerObject | ft
       }
}
End {}
}

答案1

问题是您在显示每个对象时都调用了 Format-Table。删除它即可。

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